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5.1. = f (x), , 0 , f (x) = f (x 0).

5.1. f (x) = 2 2 + 2 +1 0 = 1.

. :

1) f (x) = (2 2 + 2 +1) = 2 x 2 + 2 x + 1 = 2 × 1 + 2 × 1 + 1 = 5.

2) f (1) = 2 × 12 + 2 × 1 + 1 = 5.

f (x) = f (1), f (x) 0 = 1.

5.2. 0, 0 Î . ∆ = 0 0, ∆ = f (x) − f (x 0) = f (x 0 + ∆ x) − f (x 0) 0.

5.1. = f (x) 0 Î , = 0.

. 1 = f (x) 0 Î . , f (x) = f (x 0). = 0 + ∆ .

f (x 0 + ∆ x) = f (x 0),

f (x 0 + ∆ x) − f (x 0) = 0, ((x 0 + ∆ x) − f (x 0)) = 0,

. . = 0.

2 = 0. ((x 0 + ∆ x) − f (x 0)) = 0, f (x 0 + ∆ x) − f (x 0) = 0, f (x 0 + ∆ x) = f (x 0). , = f (x) 0.

5.2. f (x) φ() 0, f (x) + φ(x), f (x) − φ(x), f (x) × φ(x), f (x)/φ(x) , φ( 0) ≠ 0.

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, :

1) Pn (x) = Î R;

2) - R (x) = , ;

3) = sin x, y = cos x, y = tg x, y = ctg x .

5.3. z = φ(x) 0, = f (z) z 0 = φ(x 0). = f (φ(x)) 0.

, .

5.2. , = sin x 2 0 = 0.

. z = x 2 0 = 0 . = sin z z 0 = x 02 = 0, 5.3 = sin z = sin x 2 0 = 0.

5.3. , . = f (x) = f (), , f (x) . , f (x) = f (), , f (x) . , ( , ).

, , , .

5.4. ( -).

f (x) [ ] . Î [ ], f () = 0.

5.5. ( -).

f (x) [ ], f () = A, f () = B. , . [ ] , f () = C.

5.6. ( ).

f(x) [ ], .

5.7. ( ).

f(x) [ ], , . . 1, 2 Î [ ], Î [ ] f (x 1) £ f (x) £ f (x 2).

 





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