17. - , 15,0 0,20 KMnO4 50,0 0,10 Na2SO3 = 1.
. (. 16). :
n ( KMnO4) = 15,0 ∙ 103 ∙ 1,00 = 15,0 ∙ 103
n ( Na2SO3) = 50,0 ∙ 103 ∙ 0,20 = 10,0 ∙ 103 .
, KMnO4 . KMnO4. , - MnO4/Mn2+. :
n ( ) = 15,0 ∙ 103 10,0 ∙ 103 = 5,0 ∙ 103 Þ
n () = 1,0 ∙ 103
n ( Mn2+) = 10,0 ∙ 103 Þ n (Mn2+) = 2,0 ∙ 103.
15,0 + 50,0 = 65,0 = 65 ∙ 103 .
:
() =1,0 ∙ 103/ 65 ∙ 103 = 0,0154 /
(Mn2+) =2,0 ∙ 103/ 65 ∙ 103 = 0,0308 /
C (H+) = 10 pH = 101 = 0,1 /.
- :
E = + 0,059 / 5 ∙ lg () =
= 1,51 + 0,059 / 5 ∙ lg(0,0154 ∙ (0,1)8/ 0,0308) = 1,49 .
18. - /Hg Cl, Cl 0,1 /.
. Cl Hg2Cl2.
Hg2Cl2 + 2 e = 2Hg + 2Cl
- :
+ 2 e = 2Hg (4.2)
+ 2Cl = Hg2Cl2
[1; 2, . 24, 49] :
= 0,792
= 1,3∙1018
(I) Hg2Cl2. :
[ ] = / [Cl]2 = 1,3 ∙ 1018/(0,1)2 =1,3 ∙ 1016 /
(4.2) :
19. - Cd2+/Cd , 40 0,2 / CdCl2 60 4 / KCN.
. - Cd2+/Cd :
= + 0,059 / 2 ∙ lg [Cd2+].
:
Cd2+ + 4CN ↔
Cd2+ , CN. :
|
|
= = 1,29 ∙ 1017
,
= = 0,08 /
[CN] = 4 ∙ = 2,4 4 ∙ 0,08 = 2,08 /
, Cd2+ :
= 0,402 .
= 0,402 + 0,059/2 ∙ lg 3,31 ∙ 1020 = 0,977 .
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