1. 30 % ( ) NaCl 300 , 10 % ? (: 150 ).
w1(NaCl) = 30 % | (w) . |
w2(NaCl) = 10 % | |
m¢(H2O) = 300 | |
m1(NaCl) =? |
m2(-) = m1(-) + m¢(H2O) = m + 300
30m = 10m + 3000
20m = 3000
m = 150.
: 10 % , 150 30 % NaCl.
3. , 16 %- 1,149 /3. 4 .
w(All3) = 16 % | (w) All3 . All3 : |
r(-) = 1,149 /3 | |
C (All3) =? | |
C (All3) =? | |
Cm(All3) =? |
, m(-)= V(-) ´ r(-) Þ
.
1. 1 :
.
2. 1 ࠠ
m (AlCl3 )
N = ___________________
1/3 (AlCl3 ) V (-)
3. , 1 .
All3 1000 () :
(100 16) 2 | 16 All3 | |
1000 2 | m All3 |
Þ .
, [/1 2]
.
4. 0,512 100 , 5,296 . 5,5 . 5,1 . .
m(X) = 0,512 | 2 (Dt) , |
m(C6H6) = 100 | |
t(-) = 5,296 | |
t(C6H6) = 5,5 | |
K = 5,1 | |
M(X) =? |
K .
m ; m1 .
Dt = t(C6H6) t(-)
: .
5. 0,1 , .
CH3COONa + H2O Û CH3COOH + NaOH CH3COO + H2O Û CH3COOH + OH 1. : . | |
h =? | |
pH =? |
2. :
0,00758 %.
3. -:
4. :
pH = 14 + lg[] = 14 + lg7,58´106 = 8,88
|
|
: h = 0,00758 %, pH = 8,88.
6. , 0,02 /3 0,01 /3?
1. Pb(NO3)2 + 2HCl PbCl2¯ + HNO3;
2. PbCl2 (.) Û Pb2+ + 2Cl;
3. (PbCl2) =[Pb2+] . [Cl]2 = 1,6 . 105;
4. :
Pb(NO3)2 Û Pb2+ + 2NO3;
HCl Û + + Cl;
: 0(Pb2+) = 0,01 /3; 0(Cl) = 0,02 /3.
. , :
;
;
5. = (Pb2+) . 2(Cl) = 0,005 . (0,01)2 = 5 . 107;
6. 5 . 107 < 1,6 . 105; <
: , .
4.