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21 143, 147, 148.

21. (0 = 0,20 /) c 0,40 / .

. , , . .

, 100,00 (V0) H (0 = 0,20 /). (V ), HCOOH.

100,00 0,20 = V 0,40; V = 50,00 .

1. (2):

= 1/2 1/2 lg 0 = 1/2 3,75 1/2 lg 0,20 = 2,57.

2. , . (7). , , :

= ( ∙ Vo ∙ V)/ Vo; c = ∙ V/ Vo.

/c = [( ∙ Vo ∙ V)/ Vo] / ( ∙ V/ Vo) =

= ( ∙ Vo ∙ V) / ∙ V/ Vo.

,

25,00 (50 %) :

45,00 H (45,00: 50,00 100 = 90 %):

49,50 H (49,50: 50,00 100 = = 99 %):

49,95 (99,9 %), :

3. , = = = 0,2 /. (5):

4. . 20. , 50,05 (100,1%):

= 14 + lg [(50,05 50,00) 0,40/100,00] = 10,30.

50,50 (101%)

= 14 + lg [(50,50 50,00) 0,40/100,00] = 11,30.

55,00 (110%)

= 14 + lg [(55,00 50,00) 0,40/100,00] = 12,30.

. 2, (. 2).

2

VT, -
  = 1/2 1/2 lg 0 2,57
25,00 3,75
45,00 -″- 4,70
49,50 -″- 5,75
49,95 -″- 6,75
50,00 K = 7+1/2 +1/2 lg c 8,53
50,05 KOH pH = 14+lg T 10,30
50,50 KOH -″- 11,30
55,00 -″- 12,30

 

. 2. 0,20 / 0,40 /

[3] : ( 6,88,4; =8,0), ( 6,88,4; =8,0), ( 8,09,6; =9,0), ( 8,210,0; =9,0), .

 





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