10. :
) MC = MR = P;
) AR = MR > P;
) P = AC MC;
) MR = P AR.
1., .
: = 100
10 Q. , = 10 Q 100.
MR=MC
MR , ,
MR = = 10 Q 100
10 Q 120 = 100 10 Q.
20 Q = 220
Q = 11 .
2. = 10 Q 100 = (10 11) 100 = 10 . .
2. :
= 5Q + 0,25Q2
, QD = 160 .
.
MR=MC. MR ,
,
QD = 160 => = 160 Q, MR = 160 2Q.
= (5 Q + 0,25 Q2
)
= 5 + 0,5 Q
160 2Q = 5 + 0,5 Q
2,5 Q = 155
Q = 62 .
= 160 62 = 98 . . 132
3. , ˳,
1 =50%
, 2= 30%, 3= 15%.
1. ˳ : 100%
k
k
I
L = ⋅
L = (50:30) 100% = 166,7 %.
2. ˳ :
()
()
100%
3k
k k
k k
k
I
1 2
2 3
L ×
+
+
+
=.
L = ⋅
(2,22 + 2,66) 100% = ⋅
(4,88) 100% = 244%.
4. ,
ճ (-),
, =45%, =35%, 98
20%.
∑
=
=
n
1i
H i
I k
IH =452
+352
+(202
:98)=2025 + 1225 + (400:98)= 2025 +1225 + 4,08 =3254,08>1800,
, -
.
4. : , ,
, 100 . .
,
, 20%.
Q TR T AVC
400 800 1,5 1,6
1. TR = Q => = TR: Q = 800: 400 = 2 . .
2. AVC = VC: Q => VC = AVC Q = 1,5 400 = 600 .
3. TC = FC + VC = 100 + 600 = 700 .
4. ATC = TC: Q = 700: 400 = 1,75 . 133
5. = TR TC = 800 700 = 100 .
6. ↑ 20%, = 700 + (700 0,2) = 700 + 140 = 840 .
= TR TC = 800 840 = - 40 ., .
|
|
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P Q TR TVC T AVC ATC
2 400 800 600 700 1,5 1.75 1,6 -40
5. . , ,
10 . .
?
Q TC FC
0 4 4
1 8
2 18
3 39
1. FC const = 4
2. TC = FC + VC => VC = TC FC
3. FC = FC: Q
4. AVC = VC: Q
5. ATC = TC: Q
6. = ∆ TC: ∆ Q
7. TR = Q
8. R = ∆TR: ∆Q;
R = = 10 - Q, Q = 1.
9. = TR TC
10. :
) = 2 Q = 1 Q = 2;
) R = , 2.
11. < min, < 4,
AVC min < P < ATC, 4 < P < 8.
.
Q TC FC VC AFC AVC ATC C TR R
0 4 4 0 - - - - 0 - - 4
1 8 4 4 4 4 8 4 10 10 2
2 18 4 14 2 7 9 10 20 10 2
3 39 4 35 1,3 11,4 13 21 30 10 -9
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