. 4 .. :
Q, . | TC | FC | VC |
0 | 150 | 0 | |
5 | 20 | ||
15 | 40 | ||
30 | 60 | ||
50 | 80 | ||
75 | 100 | ||
95 | 120 | ||
110 | 140 | ||
120 | 160 | ||
125 | 180 | ||
125 | 200 |
1. , .
2. , .
3. , :
) ,
) .
:
1. , , :
Q | TR | FC | VC | TC | AFC | AVC | ATC | AR | MC | MR | PR |
0 | - | 15 0 | 0 | 150 | - | - | - | - | - | - | - 150 |
5 | 20 | 20 | 170 | 30 | 4 | 34 | 4 | 4 | 4 | - 150 | |
15 | 60 | 40 | 190 | 10 | 2,66 | 12,66 | 4 | 2 | 4 | - 130 | |
30 | 120 | 60 | 210 | 5 | 2,0 | 7,0 | 4 | 1,33 | 4 | - 90 | |
50 | 200 | 80 | 230 | 3 | 1,6 | 4,6 | 4 | 1 | 4 | - 30 | |
75 | 300 | 100 | 250 | 2 | 1,33 | 3,33 | 4 | 0,8 | 4 | 50 | |
95 | 380 | 120 | 270 | 1,58 | 1,26 | 2,84 | 4 | 1 | 4 | 110 | |
110 | 440 | 140 | 290 | 1,36 | 1,27 | 2,6 4 | 4 | 1,33 | 4 | 150 | |
120 | 480 | 160 | 310 | 1,25 | 1,3 3 | 2,58 | 4 | 2 | 4 | 170 | |
125 | 500 | 180 | 330 | 1,20 | 1, 4 4 | 2,64 | 4 | 4 | 4 | 170 | |
125 | 500 | 200 | 350 | 1,20 | 1,6 | 2,8 | 4 | - | - | 150 |
2. , (.5.1).
. 5.1. .
3. ) .
, ( FC = 150 .. ).
( 4 ..)
((P MC) / P = |1 / Ed|) , .
:
P = 4 = MR = AR.
: , . () . D = MR = AR. .
|
|
) .
, , :
MC = MR = .
: Q = 5 Q = 125 . Q = 5 150 .., Q = 125 . (PR = 170 ..). , Q = 125 . MC = P = 4 = MR = AR.
:
MC = P = MR = AR.
, Q= 5 . Q = 75 . , . , (FC = 150 ..) , : (FC + VC PQ) < FC( AVC < P, VC < PQ). :
, min AVC ≤ P < min ATC. .
AVC ≥ P, , .. .
75 .. AC < P.
:
: min AVC ≤ P < min ATC.
, , P ≥ min A C. , :
MR = AR = MC = AC = P.
, . . : P = AC = MC.
(. 5.2).
5.2. .
:
. ((P MC) / P = |1 / Ed|) .
(D = AR).
, (/2).
, (/2).
MCMR. TR TC.
. :
TC = ¼ Q² + 10Q + 300;
Q (1) = 400 2P (1);
|
|
Q (2) = 600 4P (2).
) , , , ?
) .
) , , ?
:
, , , . .
. : , , . .
, , .
:
) :
MC = MR (1) =MR (2),
1, 2 , .
, . , , .
:
(TC) = MC = ½Q + 10.
, :
MC = ½ (Q (1) + Q (2)) + 10.
(MR(1) MR(2)) . : MR =(TR) = (P × Q).
Q(1) = 400 2P(1), Q(2) = 600 4P(2), , :
P (1) = 200 ½ Q (1)
P (2) = 150 ¼ Q (2).
:
MR (1) =(TR) =((200 ½ Q) × Q) = (200Q ½ Q²) = 200 Q (1);
MR (2) =(TR) =((150 ¼ Q) × Q) = (150Q ¼ Q²) = 150 ½Q (2).
:
(2) (1). :
Q (2) = 2 Q (1) 100.
Q (2) Q (1):
½ (Q(1) + 2Q(1) 100) + 10 = 200 Q(1).
, , :
Q (1) = 96 ;
Q (2) = 92 .
, :
P (1) = 200 ½ × 96 = 152 ..
P (2) = 150 ¼ × 92 = 127 ..
) : PR = TR TC.
TR = (Q (1) × P (1) + Q (2) × P (2)) =(96 × 152 + 92 × 127) = 26 276 ..
TC = ¼ (Q (1) + Q (2))² + 10(Q (1) + Q (2)) + 300 = (¼ × 188² + 10 × 188 + 300) = 11 016 ..
PR = 15 260 ..
) , , ?
. , , , . (.. ).
|
|
, . :
Q (D) = (400 2P (1)) + (600 4P (2))= 1 000 6P.
:
P = 167 1/6Q.
, . Q, MC = MR.
MC = ½Q + 10;
MR = (TR) = ((167 - 1/6 Q) × Q) = (167 Q 1/6 Q²) = 167 1/3 Q.
MC MR:
0,5Q + 10 = 167 1/3Q.
, Q ≈ 188 ., ≈ 167 1/6 × 188 ≈ 136 ..
: PR = TR TC.
PR = 188 × 136 (¼ × 188² + 10 × 188 + 300) = 14 552 ..
: 708 .. (15260 14552).