.


:




:

































 

 

 

 





, :

H2O ↔ H+ +

[H+] ∙ [OH]

: = = 1,8 ∙10 16 (t=22)

[H2O]

.

 

г [H2O] = const, :

[H2O] = 1000:18=55,56 /

:

1,8 ∙10 16 ∙55,56 = [H+] ∙ [OH] = 1∙1014

, . :

  ↑t → ↑
t=22 = 1∙1014

t=30 = 1,89∙1014

t=50 = 5,6∙1014

t=100 = 74∙1014

[H+] [OH], - .

 

:

[H+] ∙ [OH] = 1014, [H+] ∙ [OH] ≠ 0, [H+] ≠ 0 [OH] ≠ 0

H+, OH .

[H+] ∙ [OH] = const, [H+] [OH]

(, ↓[H+] ↑[OH])

 

: [H+] = [OH] = √ 1014 = 107 .

: [H+] [OH]; [H+] 107; [OH] 107 .

: [H+] [OH]; [H+] 107; [OH]107 .

 

= ℓg [H+]

O = ℓg [OH]

 
 

 

 


[H+] ∙ [OH] = 1014 : ℓg [H+] + ℓg [OH] = 14

ℓg [H+] ℓg [OH] = 14





:


: 2015-10-06; !; : 412 |


:

:

,
==> ...

1526 - | 1480 -


© 2015-2024 lektsii.org - -

: 0.01 .