.


:




:

































 

 

 

 


, .

5

() , . , . , . , . , .. , . , , . ‑ . . , , .

 

.

. . . , . , ‑ , .

, , , , . , .

,

 

u(kh)=-r1u[(k-1)h]--rnu[(k-n)h]+

+t0u(kh)+t1u[(k-1)h]+ +tnu[(k-n)h]- (1.31)

-s0y(kh)-s1y[(k-1)h]- -sny[(k-n)h]

 

u ‑ ( , u ‑ () , ‑ ( ) . n . n =2. , , .

. , . "" . , (feedforward control).

(. 1.5)

 

 

. 1.7. .

 

, , .

, , , , . (feedforward from process disturbances), . . .

 

.

. . , , ‑ .

, , , . , .

, :

, . "" , , .

, .

. - , .

, .

 

, :

.

‑ .

, .

() , .

(Proportional-Integral-Derivative). , . , , .

-

 

(1.32)

u0 (), e(t) , K , Ti , Td .

- , K, Td, Ti . , , . () .

‑ . (position form) . -

 

u(k∙h) =u0 + up(k∙h) + ui(k∙h) + ud(k∙h) (1.33)

 

u0. (1.32)

 

up(k∙h)=K∙e(k∙h) (1.34)

 

 

(1.35)

(1.36)

(1.35) h Ti , , . -

(1.37)

0<β<1.

-, . (incremental form) - , , , . (k-l)h k∙h.

 

Δu(kh)=Δup(k∙h)+Δui(kh)+Δud(kh) (1.38)

 

 

Δup(k∙h)=up(k∙h)-up[(k-1)h]=K∙[e(k∙h)-e[(k-1)∙h]=K∙Δe(k∙h) (1.39)

 

 

Δui(k∙h)=ui(k∙h)-ui[(k-1)h]=K∙α∙e(k∙h) (1.40)

 

(1.41)

. , , . - . . , , . , , .

 

.

. . , . , , . , . , , . , ( 8 16), .

/ . , .. , , , .

 



<== | ==>
. | .
:


: 2017-02-11; !; : 481 |


:

:

- , .
==> ...

1565 - | 1379 -


© 2015-2024 lektsii.org - -

: 0.051 .