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. I1 = 1 I2 = 3 . r = 40 . , 10 .
:
I1 = 1
I2 = 3 :
r = 0,4 = 1 + 2
r1 = 0,1 ,
____________
-? -- :
= (μ0μI)/2πr
1 = (μ0μI1)/2πr1
2 = (μ0μI2)/2π(r − r1),
μ0 = 4π∙10-7 / ,
μ = 1 ( 1 ).
1 = 4∙3,14∙10-7∙1∙1/2∙3,14∙0,1 = 2 ;
2 = 4∙3,14∙10-7∙1∙3/2∙3,14(0,4 0,1) ≈ 0,7 .
= 2,7 .
: = 2,7 .
.
. , - = 50 /Ѱ, 1 r = 12 40 . . .
:
α = 5010-6 /Ѱ - :
|
|
|
C = 10-6 ε = αΔT
r = 12 : T1 = (T2α + ε)/ α
N = 40 :
T2 = 0 C ε = Ir
____________ :
T1 -? I = CN
: ε = CNr → T1 = (T2α + CNr)/α
T1 = (401210-6)/ 5010-6 = 9,6 C.
: T1 = 9,6 C.
