() , .. (2 ) (1 ) (. 1). , , , .
, , ( ), - .
, (1 ), , (), .. .
. 23. -110-6,5 ( : 2 100%, t.. = 15 OC)
(. 24).
1. ( ) .
2. , .. . 3 ¸ 5% [22].
3. 14- - [22]:
D0n/ D00 = [(p0n2 p2n2)/ (p002 p202)] 0,5 →
→ p21-14 = p2n = [p0n2 (D0n2/ D002)∙((p002 p202))] 0,5, (7.1)
: D00 = D00 ; D0n = D0 = D0n ; p00, p0n , , (); p20, p2n , , ().
[23] 1- ÷ 14- :
; . (7.2)
4. hi1-14 ( : θ = d / ℓ > 8 ¸ 10):
hi 1-14 = (0,92 0.2/(D0 ∙υ))∙(1+(H01-14 - 7∙102)/2∙104). (7.3)
: D0 , /; υ = (υ´ ∙ υ2 1-14)0,5 , 3/; υ2 1-14 1-14, 3/; H01-14 , /.
. 24. h,s- -110-6,5
5. ( 1-14) .
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, 14- 15- , 1-14 :
D = D0 + D0 , (7.4)
: D 15- ¸ 19- , /; D0 14- , /; D0 = (D D) , (D ≈ 0,006 ∙ D ), /).
15- :
h = (h2 ∙ D2 + h0 ∙ D0 ) / D . (7.5)
-:
p = [ (D / D 0)2 ∙ (p 02 p 02) + p 2]0,5. (7.6)
:
) ( ) . 4. (2 ) .
) : p , ;
p ≈ p 0 , .
. 4. - -88
68,49 | |||
1- | 68,44 | ||
% | 3,0 | ||
/ | 85,275 | ||
6,5 | |||
/ | 20,0 | ||
/ | 105,275 | ||
( ) | 0,0509 |
p 02 p 2 , :
p = (D / D 0) ∙ p 0. (7.7)
6. -:
D0n2/ D002 = [(p0n2 p2n2)/ (p002 p202)] 0,5 →
→ p2n = [p0n2 (D0n2/ D002)∙((p002 p202))] 0,5. (7.8)
: D00 = D0 = 105,3 / 15 ¸19; D0n = D 15 ¸19; p00 = p 0 - () ; p0n = p - ; p20 = 1,64 (1,67 /2) .
19 ( ) , .
15¸19 (hi15-19) ( : θ = d / ℓ > 8 ¸ 10):
hi15-19 = (0,92 0.2/(D ∙υ))∙(1+(H015-19 7∙102)/2∙104)∙k. (7.9)
: D 15- , /;
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υ = (υ015 ∙ υ219)0,5 15¸19 , 3/; H015-19 , /; k = 1 0,4∙(1 γ)∙ y2 ∙(H0 15-19 / H015-19) , , : : γ = 0,1 [22, 24]; y2 ; H0 15-19 (H015-19), ( x = 1 h,s-).
7. .
(p2n) () (∆p) (∆p):
∆p2 = ∆p + ∆p = (0,02 ¸ 0,03) ∙ p2n. (7.10)
p = p2n ∆p2. (7.11)
, ( ) φ = 0,98.
φ = G / G2 I, (/) /(/). (7.12)
: G (), , /; G2 I , ( ) , /.
(G2 I) :
y2 = 1 x2 = G2 I / (G2 I + D2 II) = G2 I / D2 → G2 I = y2 ∙ D2, (7.13)
: D2 = D , /; G2 I , , /; D2 II , (D2 = G2 I + D2 II) , /.
:
G = φ ∙ G2 I, /. (7.14)
, ( ):
G0 I = G2 I G. (7.15)
:
D0 = D2 II + G0 I . (7.16)
:
x0 = D2 II / D0. (7.17)
, :
D = D2 = D0, (7.18)
: D0 ( ), /; D2 , /; D , /.
[10, 11]:
hi = 0,87∙(1+ (H0 400)/104)∙k ∆H / H0 , (7.19)
: H0 , /; k = 1 0,4∙(1 γ)∙ (y0 + y2)∙(H0 / H0 ) , ; γ = 0,1 [22, 24]; y2 ; H0 (H0), ( x = 1 h,s-).
, [22, 24], /:
∆H = 0,5∙103[(D ∙ υ) / ΩZ]2 ∙ [1 (0,1/(θZ 1)], (7.20)
: D , /; υ ( ), 3/; ΩZ = π ∙ d Z ∙ ℓ2 Z = 3,14∙2,48∙960,0∙103 = 7,475712 2 -110-6,5; θZ = d Z / ℓ2 Z = 2,48 / (960,0∙103) = 2,583 -110-6,5 [ 23 ]; d Z = 2,48 -110-6,5; ℓ2 Z = 960 -110-6,5.
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8. :
∆H, hi , Hi, h2 (7.21)
9. , [22], , :
p = p2; h = h2 ; t = t2 ; υ = υ2 ; y = y2 . (7.22)