: | : | |
ω () = 15% m () = 250 | 1. , (ω = 15%): | |
m (H2O) =? m () =? | ||
2. , : m (H2O) = m () m () m (H2O) = 250 37,5 = 212,5 | ||
: | ω=15% 37,5 212,5 . |
, 1.6 10%?
: | : | ||
ω () = 10% m () =1,6 | 1. : 1,6 = 1600 | ||
2. m(NH4Cl), (ω = 10%): | |||
m (NH4Cl) =? | |||
: | ω=10% 160 . | ||
12 , 5%?
: | : |
ω () = 5% m (NaCl) = 12 m (H2O)=? | 1. ω = 5%: |
2. , : m (H2O) = m () m (NaCl) m (H2O) = 240 12 = 228 | |
: | ω=5% 228 . |
2. |
.
: | : |
V = 500 3 m(Cu2+)= 0,2 /3 m(CuSO4*5H2O) =? | 1. (CuSO4*5H2O): = 63,546 + 32,06 + 16*4 + 5*(2 + 16) = 249,61 / |
2. 1 : (5H2O) = 5 * (2 + 16) = 90 / | |
3. : 249,61 / (CuSO4*5H2O) 90 / () 100 % (CuSO4*5H2O) - x % () =36,06 % : CuSO4*5H2O 36 %. |
(CuSO4*5H2O) : 8,5746 , 9,3310 , 9,0610 . .
: | : | |
m ( ) = 9,3310 m () = 8,5746 m (. . .) = 9,0582 ω(H2O)=? | 1. : m () = m ( ) m () m () = 9,3310 - 8,5746 = 0,7564 2. , : m (H2O) = m ( ) m (. . .) m (H2O) = 9,3310 9,0582 = 0,2728 3. : | |
: | 36% | |
|
|
3. |
1. 250 C (CaCl2*6H2O) = 0.5 /?
: | : |
V = 7,5 C(x) = 4,2 m (CaCl2*6H2O) =? | 1. CaCl2*6H2O: = 40,08 + 35,453*2 + 6*(2 + 16)=218,986 / 2. : : 250 CaCl2*6H2O = 0,5 / 27,3733 . |
4. . |
1. (Na2B4O710H2O) 100 f (Na2B4O710H2O) = 0,1 /?
: | : |
V- = 100 f = 0,1 / m (Na2B4O710H2O) =? | 1. Na2B4O710H2O: = (222,99+410,81+716)+1018,02=381,42 / 2. Na2B4O710H2O: f =1/2 f = f 3. : : 100 Na2B4O710H2O f = 0,1 / 1,9070 . |