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= t / (1 + E) t = C t (1 + E) t,
() t, ; C t - () t;
( r) _____________________________.
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____________________________________________ ________________________________________________ .
v | = i + b + , i ; b - ; , . | |
v | ||
v | ||
v |
3.4
_________________________ : _________________________________________________________.
= ACF | R = ARR | = NPV | = IRR | |||||
= PP | = DPP | = PI | ||||||
, | ||
v | () | = ∑ t - ∑ t t=1 t=1 |
v | - , , - , | ∑ t / ∑ t = 1 t= 1 t=1 |
v | R = ∑ / ∑ t t =1 t=1 |
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, _______________________________________ .
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: = ∑ (Rt t) (1+ E)- t - ∑ Kt (1 + E)- t t=0 t=0 | (): = (∑ (Rt t) (1+ E) t) / ∑ Kt (1 + E)t t=0 t=0 |
: ∑ (Rt t) (1+ E) - t = ∑ Kt (1 + E) - t t=0 t=0 = 1 + ( 1 (2 + 1) / (1 + 2)) | : ∑ (Rt t) (1+ E) - t = ∑ Kt (1 + E) - t t=0 t=0 = t t / ( t+1 t) |
: Rt - , t- ; E ;
t - , t- ; T ;
Kt - t- .
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1- | 2- | 3 | ||
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= ∑ t / (1 + )t - 0 t=1 | 1 = 4 / 1,1 + 4 / 1,1 2 + 5 / 1, 13 5 = 5,7; 2 = 4 / 1,1 + 5 / 1,1 2 + 6 / 1,1 3 6 = 6,3. : 1 > 2, 2 1. | |
= ∑ t / (1+ )t / 0 t=1 | 1 = (4 / 1,1 + 4 / 1,1 2 + 5 / 1,13): 5 = 2,14; 2 = (4 / 1,1 + 5 / 1,1 2 + 6 / 1,13): 6 = 2,05. : 1 < 2, 1 2. | |
: ∑ t / (1 + )t = 0 t=1 1 + - - - - - - - - - - - - - - 0 1 2T - 5 - | 1: ) 1 = 4 / 1,1 = 3,64; ) 2 = 4 / 1,1 + 4 / 1, 12 = 6,94; 5 3,64. ) = 6,94 3,64 = 0, 412 150 . 1 = 1 150 . 2: ) 2 = 4 / 1,1 = 3,64; ) 2 = 4 / 1,1 + 5 / 1,12 = 7,77; 6 3,64. ) 2= 7,77 3,64 = 0, 54 197 . 2 1 197 . : , 1 2. | |
∑ t / (1 + )t - 0 = 0 t=1 -__ + 5 ........... 0 50 100 - 5 - = 5,7 = 10% = 0,9 = 50% | ( - ). , = 0,5.: 1) 4 / (1 + ) + 4 / (1 + ) 2+ 5 / (1 +) 3 5 = 0; f (E) = 4 / (1+) + 4 / (1+ ) 2+ 5 / (1+) 3 5; f (E) = - 4 / (1+) 2- 8 / (1+) 3 15 /(1+)4, = 0,5, 1, 2, 3: 1 = 65, 124%; 2) 4 / + 5 / 2 + 6 / 3 6 = 0. : 2 = 58,8 %. : 1 |
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