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- , , . . :

, ( ) .

, , , .

, .

.

, .

() , .

, . :

1) , .. . (Q, ).

2) , - . (A, ).

 

: I- , .. , , , .

I- :

) :

dQ =dU + dA,

d , d .

) :

Q = A + DU,

DU = U2U1 .

U , . , . , , . , , , . ( ), :

dA = dV,

, dV , V,

= DV.

, , . :

) - :

V = nRT.

) - :

U = f (T)

(=const)

V = nRT=const, V = const 1V1 = 2V2 , P1 P2,V1 V2 .

U = f (T) = const, Þ DU = 0, Q = A = DV,

Q = A = nRT ln(V2/V1) = nRT ln(P1/P2)

(V=const)

: = const =

, DV = 0, : A = DV = 0 Þ Qv = DU.

Qv = DU = nCvD,

v . Cv = (3/2)×R12,47 /(×), (, 2): Cv = (5/2)×R 20,78 /(×); : Cv = 3R=24,93 /(×).

(=const)

: = const =

D = DU + pDV,

Q = DU + A, Q = DU + pDV, , , , .

Q = D = nCD,

. 1 : v = R

(dQ =0).

: =const, = , g = /v.

: A = DU, = -DU = nCv(1-2)

, : - (1 = =1,013×105 = 760 . .), - (H×), - 3 [13 = 103 3 () = 106 3()], - (00 = 273).

(..) , = 1 = 101325 , = 273 ; - = 1 = 101325 , = 250 = 298 .

.

, - ( , , , ..).

, ( ), , , . :

QV = DU

Q = D

:

D =DU + DnRT

Q= QV + DnRT,

Dn - , , ..:

Dn = Sn() - Sn(),

Sn.() ; Sn.() ( ).

, .

, . . , , D DU, . , , , , . . , , : , . :

= -QP, = -QV.

. , ( ). ( = 1 = 1,013×105, =298 ). D0 ( 0 ).

. () + 2() = 2() ΔHº = 393,5 . , 163960 ?

n(C) =

m(C) = n(C)×M(C) =416,67×12 = 5000 .

 

, :

I . , :

D- = Sn D - Sn D

, :

a + b Þ + dD

D0- = (aD0.A+ bD0.B) - (D0.+ dD0.D).

1 ( 2 2).

. :

C25OH () + 3 () = 3COOC25 () + 2 ()

250, :

: DH0.(C25OH()) = -1366,9 /, DH0.(3()) = -873,8 /, DH0.(3COOC25()) = -2254,2/, DH0.(2()) = 0 /. . C25OH () + 3 () = = 3COOC25 () + 2 () :
DH0- -?

DH0- = DH0.(C25OH()) + DH0.(3 ()) - DH0.(3COOC25()) -
- DH0.(2 ()) = -1366,9 -873,8 - (-2254,2) 0 = 13,5 .

 

II . , :

D- = SnD - SnD

, :

a + b = + dD

D0-=(D0.+ dD0.D) - (aD0.A+ bD0.B).

1 , , .

. .

. , 250:

F2O3 () + 3 () = 2Fe () + 32 ()

:

 

DH0.(Fe2O3()) = -821,32 /; DH0.(O()) = -110,5 /; DH0.(Fe()) = 0 /; DH0.(O2 ()) = -393,51 /. . F2O3 () + 3 () = 2Fe () + 32 () , :
DH0- -?

DH0- = 2DH0.(Fe()) + 3DH0.(O2()) -DH0.(Fe2O3()) - 3DH0.(O()) = -3×393,51 + 821,32 + 3×110,5 = -27,71 .





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