.


:




:

































 

 

 

 


.




. , : .

, .

u=u0(t), (4.1), (4.2) X0 (t) I0=I[u0(t)], (4.3).

u(t)=u0(t) + du(t), "tÎ[t0,tk], (4.4)

du(t) , .

, ,

, tÎ[t0,tk]; (4.5)

dX(t0)=0. (4.6)

t= t0 t= tk - l(t)=(l1(t), l2(t),, ln(t))

(4.7)

,

(4.8)

(4.8) (4.7)

, - l(t) :

"tÎ[t0,tk]; (4.9)

l(tk)=0. (4.10)

(4.4)

(4.11)

H 0=H(t, X0, u0, l)= - f0 (t, X0, u0) + < l (t), f0 (t, X0, u0)>. (4.12)

, du = (du1(t), du2(t),, dur(t)), dI (4.11), :

"tÎ[t0,tk]; (4.13)

, u(t)=(u1(t), u2(t), , ur(t)), "tÎ[t0, tk ], (4.4), dui, i=1,...,r (4.13).

, dui, i=1,...,r, "tÎ[t0, tk ] (4.3) . , dI, DI. DI=I - I0 , DI³0, |dui|, i=1,...,r.

 

.

, .

1.

u0(t)=(u10 (t), u20 (t), , ur0 (t)), "tÎ[t0, tk ].

2. t= t0 t= tk (4.1)

= fi (t, X(t), u0(t)), i=1,...,n,

(4.2) - h. X0(t)=(x10 (t), x20 (t), , xn0 (t)), "tÎ[t0, tk ] xi0 (tk), i=1,...,n t=tk.

3. (4.3)

,

,

,

h= .

(4.1)

(t)=f0 (t, X0(t), u0(t)), xn+1 (t0)=0.

I[u0(t)] = x0n+1 (tk).

4. , i=1,...,r, 5, 9.

5. t= tk t= t0 (4.1), (4.9)

xi(tk)= xik, i=1,...,n; li(tk)= 0, i=1,...,n; xik, i=1,...,n 2 tk .

6.

, i=1,...,r, "tÎ[t0, tk ].

7.

dui(t)=q× , i=1,...,r, "tÎ[t0, tk ],

q - .

8.

ui(t)=ui0(t) + dui(t), i=1,...,r, "tÎ[t0,tk]

q , 2 ( ).

9. I=I[u0+q ] I0=I[u0(t)].

I0I,

q=b×q, bÎ(0,1)

u(t)=u0(t) + q I , I0>I.

I0<I,

q=a×q, a>1

, .

10.

I[u0+du]-I[u0] ½£e,

e- , .

, ; , , 2.

 





:


: 2016-11-18; !; : 409 |


:

:

, , .
==> ...

1477 - | 1386 -


© 2015-2024 lektsii.org - -

: 0.057 .