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, . (2.1).

X0 , a0 , . , XkÎEn ak>0 k³0. ej=(0,,0,1,0,,0) , j- 1, , j=1,,n.

Sk=ejk, jk=k-n +1, (2.13)

- k/n. (2.13) e1,,en, .. S0=e1,, Sn-1=en, Sn=e1,,

S2n-1=en, S2n=e1.

f(X) X= Xk+ akSk

f(Xk+ akSk) < f(Xk). (2.14)

,

Xk+1= Xk+ akSk, ak+1=ak. (2.15)

, (2.14) , f(X) X= Xk -akSk

f(Xk - akSk) < f(Xk). (2.16)

(2.15)

Xk+1= Xk - akSk, ak+1=ak. (2.17)

(k+1) , (2.14) (2.16). , (k+1)

k+1=Xk, ak+1= (2.18)

lÎ(0;1) , . (2.18) , n e1,,en ak , ak n . n , ak .

. , .

, , x ix j, .. x i, i=1,,n.

, .

 

.

f(X) ej, j=1,,n . en , , , :

|f(Xk) - f(Xk-n)|<e || Xk - Xk-n||<e, (2.19)

e>0 - .

min{f(Xk - a×Sk) |aÎR} (2.20)

. .

0. e>0, X0ÎEn, f(X0), k=0.

1. j=k-n +1, Sk=ej, k/n.

(2.20), .. ak=arg min{f(Xk+a×Sk)|aÎR}. Xk+1= Xk+akSk f(Xk+1).

2. j<n, k=k+1 1, 3.

3. (2.19). , 4, 1, k=k+1.

4. , X* Xk+1, f*f(Xk+1).

f(X). , , , , . .

 

-

 

(2.1) , Xk-Xk-n Xk, k=s×n, s . -.

- :

1) f(X);

2) .

X Dj, j=1,,n.

1. =X, j=1.

2. Y= - Djej, ej - j- . f(Y)³f(), 3, 4.

3. Y= +Djej. f(Y)³f(), 5, 4.

4. =Y.

5. j=j+1. j£n, 2. , .. , f()<f(X), ¹X.

, =X. . ||D||£e, e , X*=X. , Dj=Djg, gÎ(0;1) .

-.

0. X0ÎEn, D=(D1,, Dn), gÎ(0;1), e>0, k=0.

1. Xk k. k ¹Xk, 3, 2.

2. ||D||<e. , 5, Dj=Djg 1.

3. k k-Xk X= k+( k-Xk)=2 k-Xk.

4. X . f()<f( k), Xk= k, k =X 3. k=k+1, Xk=X 1.

5. , X*=Xk, f *=f(Xk).

 

.

2.2.2 , f(X) .

X0ÎEn. (. 2.2.2), ..

Xn= X0+

ej , j 1, 0, j=1,,n. - a

a j =arg min {f(Xj-1+a ej) ½aÎR}.

f(X) : Sn+1=Xn-X0: Xn+1=Xn+an+1Sn+1, an+1 Sn+1 a:

a n+1 =arg min {f(Xn+aSn+1) | a>0}.

X0=Xn+1, . , (2.19).

 

 

1. f(X)=5x12+5x22+8x1x2 X0= (5;5) .

, - , 135 1. 3 .5. X , , f(X). , .

1  
K X1 X2 F(x)  
         
  -4      
  -4 3,2 28,8  
  -2,56 3,2 18,43  
  -2,56 2,05 11,8  
  -1,64 2,05 7,55  
  -1,64 1,31 4,83  
  -1,05 1,31 3,09  
  -1,05 0,84 1,98  
  -0,67 0,84 1,27  
  -0,67 0,54 0,81  
         
                 

 

,

.5.

( 1).

 

2. f(X)=(x1+1)2+x22 - X0=(2;3)T.

D=(2;3)T. f(X0)=18. , 4, X0

x1(1)=2+0,5=2,5; f(2,5;3)=21,25 ();

x1(1)=2-0,5=1,5; f(1,5;3)=15,25 ();

x2(1)=3+1=4; f(1,5;4)=22,25 ();

x2(1)=3-1=2; f(1,5;2)=10,25 ().

. X1=(1,5;2)T X1-X0 X2=2X1- X0:

x1(2)=2×1,5-2=1; x2(2)=2×2-3=1; f(1;1)=5.

X1=(1,5;2)T:

x1(3)=1+0,5=1,5; f(1,5;1)=7,25 > f(X2) ();

x1(3)=1-0,5=0,5; f(0,5;1)=3,25 < f(X2) ();

x2(3)=1+1=2; f(0,5;2)=6,25 > f(X2) ();

x2(3)=1-1=0; f(0,5;0)=2,25 < f(X2) ();

f(X3)=2,25< f(X1)=10,25 X1 X2=(1;1)T , X3

X4=2X3- X1:

x1(4)=2×0,5-1,5=-0,5; x2(4)=2×0-2=-2; f(-0,5;-2)=4,25.

X4=(-0,5;-2)T:

x1(5)=-0,5+0,5=0; f(0;-2)=5 > f(X4) ();

x1(5)=-0,5-0,5=-1; f(-1;-2)=4 > f(X4) ();

x2(5)=-2+1=-1; f(-0,5;-1)=1,25 < f(X4) ().

f(X5)=1,25< f(X3)=2,25 X3 X4 , , f(X) , . . .6 . f(X)=(x1+1)2+x22 X*=(-1;0). , . .

.6. .7.

- ( 2). ( 3).

 

3. f(X)=2x12+x22-x1x2 X0=(2;2)T(.7).

f(X) , x1 67,5. (. 2.2.2) X0 -e1=(-1;0), .. f(X0 ae1) a>0 . X1=X0- a1e1, a1=arg min{f(X0 ae1)|a>0}. , f(X)=const. X1 -e2=(0;-1) X2=X1-a2e2, a2=arg min{f(X1 ae2)|a>0}. X2 X2- X0. f(X) , .





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