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2.3.1

= β×V×KHa.

β = × (1 - ) + .

y ba= 0,5,

I X=0,77 /2, .8, 2/.

= 1,10 /2, .15, 6/.

β = 2,4(10,77)+0,77=1,322.

 

 

:

/,

 

/2, .16/;

9 8- .

KHV = 1,05 /2, . 17, 10/;

, H ≤ 350HB KHa=1 /2, .19/.

= β×V ×KHa = 1,322×1,06 ×1 = 1, 4.





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