4.3.1 = 400 . : Ft = 4000 H; Fr, =1500 H Fa = 1000 ; . 4.11. : 40, - , 240... 260 , = 650 . . .
. 1 K = 3, . , Ft, Fr Fa , - .
2 f = 0,08 (. 4.11), ().
3 Fa
M = Fa / 2 = 1000×200 / 2 = 100 × = 100000 ×.
4 Fa (4.1) (4.2)
= 47,5 .
5 M (4.3)
= 6,09 .
P , . . P = P 1 = 47,5 .
6 (4.4)
.
d = 60 (. 2.11), : d = 60; d 1 = 0; = 0,3; E 1 = 2,1×105 ; ( ) : d 2 = 95; d = 60 ; = 0,3; E 2 = 2,1×105 , d 2 .
(4.5), (4.6)
= 1 0,3 = 0,7;
= 2,63.
(4.4)
= 45,2 .
6 (4.9)
u = 5,5(Ra1 + Ra2)= 5,5(0,8 + 1,6) = 13,2 ,
Ra1 = 0,8, Ra2 = 1,6 4.11.
7 . , , (4.11)
= 45,2 + 13,2 + 0 = 58,4 .
8 , = 650 , (4.14)
.
9 , [ P ] max, . . , , (4.13)
= 185,9 .
10 (4.12) ( )
|
|
N max = [dmax]+ = 185,9 + 13,2 = 199,1
11 . ( ) 0,14%, .. (t) = 0,9986.
N min ≥ N min; N max ≤ N max.
12 10, Ø 60 7/u7, N min = 66 , , N min= 58,4 , N max= 108 N max = 199,1 .
, , , N min=108 . , 199,1 .
4.3.2 b ´ d = 150 ´ 6 ( 4.12); F, , 80 . 3, - 2.
. 1 .
d0 = (1,8... 2) d = (1,8... 2)6 = 10,8...12 .
d0 =12.
2
F1 ¢= A ∙ k ∙[ t ] = 113×1×140 = 15820 ;
: 2.
3
= 5,05.
z = 6.
, 2 3 (. 4.12).
4 e p
p = 3 ∙ d0 = 3 ∙12 = 36, p = 50
e = 2 ∙ d0 = 2 ∙12 = 24 , e = 25 .
4
= 185 = 280 ,
,
= 13300 .
5
= 117 < = 160 .
.