.


:




:

































 

 

 

 


. .




.

:

,

Ft2=Fa1=2T2/d2 = 2×113×103/160=1412,5

 

,

Ft1=Fa2=21d1 = 2×11,3×103/32=706,25

Fr2=Fr1=Ft2 tg α = 1412,5×0,36=508,5

.

l2=184 ; d= 160

 

 

:

 

 

:

:

RD = = √353,1252+131,422=√141968,58=376,787

RE = = √353,1252+377,0762= 516,61

 

(9.9)

S3= 0,37×376,767=139,41

S4= 0,37×516,61=191,1457

= 0,37 (. . 9.18)

(. . 9.21)

S3 < S4; Pa3 = Fa2 ≥ S4 - S3; 3 = S3;

4 = S3 + Fa2 =

7207. , .

4/r4 =1551,91/191,1457=8,12;

(9.5); V= 1; K = 1,3 =1, Y=0,87 = 0,41 (.. 9.18 7);

4 = (0,41×516,61×1+0,87×1551,91)×1,3=2031= 2,03

, .., (9.1)

L = (/ 4)3 = (38,5/2,03)3≈6751 ..

 

C= 38,5 (..375)

,

Ln = L 106/60n =6751×106/60×1444=77920,13

n = 1444/ -


6. .

2

(10.1) - ,

∆t = tM - tB = P(l-η)Kt A≤[∆t]= = > [∆t]=

 

= - ,

Kt = /(2 Ѱ)

[∆t]=

∆t .

∆t/[∆t] =,

 

 

. .

. - , , , , ' .

- , , , . ; .

. . .

. . III . . .

. .

, .

: b h 1 = × × ,

b h 1= × ×

b h 1 = × × .

 





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