.
I. 2 :
1.1
W /3
H2O..=
H2O.=
:
1.2
K..=(100-4,174)/100=0,958
..=(100-4,741)/100=0,953
:
1.3
i i
:
2=K.∙2=0,958∙10=9,583 %
=K.∙=0,958∙27,4=26,256 %
H2=K.∙ H2=0,958∙3,3=3,162 %
H4=K. H4=0,958∙0,9=0,862 %
N2=K.∙ N2=0,958∙58,4=55,962 %
O2+CH4+C2H4+N2+2+H2O.≈100%
2 | H2 | H4 | N2 | ||
, % | 9,583 | 26,256 | 3,162 | 0,862 | 55,962 |
:
2= . ∙2=0,953∙3=2,858 %
CO= . ∙=0,953∙7,4=7,049 %
H2= . ∙H2=0,953∙56,4=53,726 %
H4= . ∙H4=0,953∙26,2=24,958 %
N2= . ∙N2=0,953∙6,5=6,192 %
O2=0,953∙0,5=0,476 %
2+CO+H2+H4+N2+ O2 +H2O..≈100 %
2 | H2 | H4 | N2 | O2 | ||
, % | 2,858 | 7,049 | 53,726 | 24,958 | 6,192 | 0,476 |
100%, , .
II. .
QHp=127CO+108H2+358CH4+590CmHn+560C2H2+636C2H6+913C3H8+
+1185C4H10+1465C5H12+234H2S [/3] 1.4
QHp=QHp()∙+ QHp()(1-) 1.5
QHp()=127∙27,4+108∙3,3%+358∙0,9%=4158,4 [/3]
QHp()= 127∙7,4+108∙56,4%+358∙26,2%=16410,6 [/3]
1.5
= QHp- QHp() / QHp()- QHp()=6100-4158,4/16410,6-4158,4=0,1585
=0,1585 (1-)=0,8415
QHp= QHp() ∙+ QHp()∙(1-)+=16410,6∙0,1584+4158,4∙0,8415=
=6100,37 [/3]
:
1.6
2()= 2,858∙0,1585+9,583∙2,858=8,517 %
()= 7,049∙0,1585+26,256∙0,8415=23,212 %
H2()= 53,726∙0,1585+3,162∙0,8415=11,176 %
H4(c)= 24,958∙0,1585+0,862∙0,8415=4,681 %
N2(c)= 6,192∙0,1585+55,962∙0,8415=48,076 %
2()= 0,476∙0,8415=0,075 %
H2O()=4,741∙0,1585+4,174∙0,8415=4,264 %
O2()+ ()+ H2()+ H4(c)+ N2(c)+ 2()+H2O()=100,001 %≈100 %
100 %, , .
1.1
, % | , % | , % | |
O2 | 9,583 | 2,858 | 8,517 |
CO | 26,256 | 7,049 | 23,212 |
H2 | 3,162 | 53,726 | 11,176 |
H4 | 0,862 | 24,958 | 4,681 |
N2 | 55,962 | 6,192 | 48,076 |
2 | - | 0,476 | 0,075 |
H2O | 4,174 | 4,741 | 4,264 |
: | 99,999 | 100,001 |
|
|
:
VO2=0,01∙((0,5(CO+H2))+(m+0,25∙n)∙ H4 O2) 1.7
:
VO2=0,01∙[0,5(23,212+11,176)+2∙4,681)-0,075] =0,265 3/3
:
L0=(1+)∙ V2 1.8
:
L0=(1+3,762)∙ 0,265=1,26 3/3
:
:
3/3
3/3
3/3
3/3
:
1.9
3/3
CO2=(VCO2/V)∙100%=(0,364/2,173)∙100%=16,75%
H2O=(VH2O/ V)∙100%=(0,205/2,173)∙100%=9,43%
N2=(VN2/ V)∙100%=(1,577/2,173)∙100%=72,57%
O2=(VO2/ V)∙100%=(0,0265/2,173)∙100%=1,22%
:
1.10
:
, .. =105
CO2=p∙(CO2/100%) 1.11
pH2O=p∙(H2O/100%) 1.12
CO2=p∙(CO2/100%)=105∙(16,75/100%)=16,75
pH2O=p∙(H2O/100%)=105∙(9,43/100%)=9,43
2.1
. 2.1 : t - ; t, t -
n
L
:
: h = 1,6, hg=0,55
: H = 2,6, H=2,2
: h = 1
: :
.
, 3 : , , . ε., , , ε. ε. ε .