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The operational standards for the reference of the international chain of 27 500 km long




Channel (Truct) Transmission speed Mbit/s The value of B operational standards
ESR SESR
MDC 0,064 0,04 0,001
    CT 1.5 5.0 0,02 0,001
5.0 15 0,025 0,001
15 55 0,0375 0,001
55 160 0,08 0,001
160 .   -

Table.P-15.3.

Some of the operational standards,
taking into account the actual length and type of area the primary network

Backbone PN Intrazone PN
Length L Less or equal (km)   D1 Length L Less or equal (km)   D2
  0,015   0,026
  0,02   0,040
  0,022   0,052
  0,024   0,065
  0,026   0,075
  0,027    
  0,029    

2. We define the boundary values of errors S1 and S2 during the selected time sec.

 

(Table.P-15.2)
S1 = R0 2

S2 = R0 + 2

3. Compare the measured value of the parameter S - S(ESR) or S(SESR) to the threshold values of S1 and S2.

If

S < S1, then the input of the CT in operation is allowed,

If

S > S2, the measurement of the CT for the operation is not good,

If

S1 < S < S2, for the assessment of the possibility to enter the CT in operation it is necessary to continue measuring, increasing the time of measurement.

 

 

Bit error ratio BER:

BER = (Nbit-err/ Nbit-sum) for the time of the measurements meas

In accordance with the definition of NES and NSES

Nbit-err= NES + 300* NSES

There are 300 = 30% of 1000 blocks with one or more errors per second.

Nbit-sum= meas ( sec )* 2,048*106 bit

In its turn

NES = ESR * meas (sec)

NSES = SESR*meas (sec)

So

BER = (ESR * meas +300* SESR*meas)/ meas * 2,048*106

BER = (ESR +300* SESR)* 5*10-7

BER = ESR * 5*10-7 + SESR* 1,5*10-4

 

       
 
BER ≈ SESR* 1,5*10-4
   
(Table.P-15.3.)

 

  If we believe that SESR=0, taking into account only the background bugs

       
 
BER ≈ ESR * 5*10-7
 
(Table.P-15.4)  
 

 

 


Link of BBER with coefficients ESR, SESR and BER:

 

BBER = NBBE/NB

BBER = ESR*NS/(1000*NS - 300*SESR*NS)

BBER = ESR*10-3/(1- 0.3*SESR)

 
 
BBER ≈ ESR*10-3

 

 


So-as the length of the block E1 is 2048 bits, the

BER ≈ BBER*5*10-4
 
 
(Table.P-15.5)

 

 


(Table.P-15.4)
Which coincides with

 

 

Let us consider an example-1:

Determine the long-term norms of quality indicators in the digital path E1 zone area length L = 240 km on the basis of .

For intra-zone area = 2 = 0,075;

 

Quality factor Calculations Number
ESR 0.04 0,075 = 0,003 310-3
SESR 0.002 0,075 + 0.0005 = 0,00065 6,510-4
BBER 3 ´ 104 0,075 = 0,225 104 2,210-5
BER
  taking into account only the background bugs

ES

0,225 104 5*10-4 = 1,125 108 310-3 5*10-7= 1510-7 1,12510-8 1.510-9
BER on the basis of the background error ES, and grouping error SES     6,510-41.510-4 = 9,7510-8 10-7

 


 

Consider the example of an-2:

Determine the short-term (operational) norms of quality indicators in the digital path E1 example 1.

In our example

R0 (ESR) = 0.02x0.075x0.5 = 7,5x10-4

R0 (SESR) = 0,001x0.075x0.5 = 3,75x10-5

 

Boundary values of an indicator of the quality of the ESR.
Let the time of measurement ESR is 24 hours (i.e T=.246060 sec = 86 400 sec).
Then

S1( ESR ) = 7,5x10-4 2 = (7.5 - 1,75)x10-4 = 5.7510-4

S2( ESR ) = 7,5x10-4 + 2 = (7.5 + 1,75)x10-4 = 9,2510-4

  Boundary values of an indicator of the quality of SESR To S1(SESR) > 0, it is necessary to increase the time of the measurements up to 5 days or more. At 7 daily measurements.

S1( SESR ) = 3, 75x10-5 2 = (3.75 1.58)x10-5 = 2.17x10-5

S2( SESR ) = 3, 75x10-5 + 2 = (3.75 + 1.58)x10-5 = 5.33x10-5

 





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