: , .
: (1). . , . .
/* 2
: x = sqrt(2) = 1.4142, z = 0.2000 */
#include <stdio.h>
#include <math.h>
void main()
{ double x, z;
printf("\n\n\t *** 2 *** \n");
printf(": .., -11, 13 \n");
printf(" x:\t ");
scanf("%le", &x); // &?
printf(" : x=%.4le \n", x);
z = (2.0 - exp(1.- x*x/2.)) / (3. + sqrt(sqrt(2.) * pow(x,3)));
printf(": z=%.4le \n", z); //
} // 4 z
:
(2.0 exp(1. x * x / 2.)) / (3. + sqrt(sqrt(2.) * x * 3))
↓ ↓ ↓ ↓ ↓ ↓ ↓ ↓ ↓ ↓ ↓ ↓
5 4 3 1 2 12 11 10 6 7 9 8
8 3 int 3.0 double.
:
1. y = logab, >0, b>0?
2. (1), k- 2.
3. (1). = 1?
4. float double. y = 1.0 / 3.0 printf(\n float = %.20f double = %.20lf , yfl, ydb);