.


:




:

































 

 

 

 


. 2




2

1. .

2. ?

3. , ?

4. ?

 

3

3

1.1 .

1.2 .

. - p-n .

(. 3.1 , ), .

U0=I0RU=0; U1 U=U0; R .


 

3.1

 

, , , , .

. p-n . (. 3.2,) .

 

 

3.2

 

,

U2 Ux=eU3; U3 , U =0.

:

1) ;

2) , ;

3) ;

4) ;

5) .

Workbench 5.0 , 3.3. DA1, ‑ DA2.

 

3.3

[3].

.

Analysis/ Parameter Sweep. . :

 

Component V1
Parameter Voltage
Start Value  
End Value 0.05(n+5) V
Sweep Type Linear
Increment Size 0.005 V
Output node DA1

n

Sweep for: DC Operation point.

Simulate. .

.

:

 

Component V1
Parameter Voltage
Start Value  
End Value (n+5) V
Sweep Type Linear
Increment Size 0.05 V
Output node DA2

n

.

3

1. ?

2. .

3. ?

4. ( ) () ?

5. ?

 

4

1.1 .

1.2 Workbench 5.0.

, . , .

, ,

, (1)

‑ ; (t) ‑ .

k(t), (t2 - t1):

,

k =1, 2, 3,..., m; n =1, 2, 3,..., m .

, , , .

k(t)

,

.

k(t) ,

.

, ,

. (2)

, (t) (t2-t1) k(t). m .

, , .

, . sin(n w0 t) sin(m w0 t), sin( w0t) cos(m w0 t), cos(n w0 t) cos( w0 t), . (t) (to,to +2p/w0) () :

,

t0<t<t0 + .

ai :

:

,

,

.

, (k =0, 1, 2,...) (to, to +2p/w0) to.

k = , I = , ¹ I =0.

, (t)

.

T w0=2p/; 2w0; w0;...; nw0. (t) , w0, 2w0 .. ().

, : (. 4.1 , ). , , , 0 90.

 


4.1 () ()

 

, , , (t) ‑ , .

() , . : , , . , ( ) . : K K.

,

Ui i- .

, 0 1. =0.

,

U1 .

, ,

.

, 0 ∞.

, ( ≤0,1 1%. =0.

Workbench . , . , .

:

.

: Xm, T0 t. . , (. 6.8):

Q = T /t,

, (duty cycle):

q =t/ T.

:

3.1 , 4.2 .

 


 

4.2

 

3.2 . , 4.2 . . .

3.3 .

3.4 Frequency (n) , n , Duty cycle 50, Amplitude 11 , Offset 0.

3.5 . . Time base 0,5 /. Channel A 5 /.

3.6 Analysis/Analysis Options... Instruments Pause after each screen . , , .

3.7 Analysis/Activate , .

3.8 , , (, ).

3.9 , Analysis/Stop .

.

3.10 . Analysis/Fourier... , Fundamental Frequency (n) , Number of harmonics 75. Simulate .

3.11 ( ) 1. Total harmonic distortion ( ). .

3.12 . Duty cycle (n). , 3.7 ‑ 3.9

3.13 , 3.10 ‑ 3.11. 1.

3.14 Duty cycle 50 (100- n).

3.15 . Duty cycle n. , 3.7 ‑ 3.9

3.16 , 3.10‑3.11. 1.

3.17 Duty cycle 50 (100- n).

1

/ Duty cycle
         
    n    
         
    100- n    
    n    
         
    100- n    

1. ?

2. ?

3. ?

4. 1?

5. Duty cycle?

 

5

1.1 RC

1.2 RC RC .

RC R C. f U, ( ) f U, , T , ∆t () () . RC . , RC KU 0 1. f KU j . KU (f) - (), j(f) - () RC .

RC C, , . RC (). , . , . , RC . , t1 t2 RC

.

RC ().

, , fcp, ..

.

, (f > fcp) .

RC , , (). 0 fcp.

3.1 RC

, (), RC 5.1.

5.1 RC

 

: R =2 n , = n , n .

, , ( 5.2). , ( ). , ( C R).

5.2 () () RC

RC EWB (. 5.3).

Analysis AC Frecuensy - - . ( 5.3): (Start frequency) n ; (End frequency) 10000 ; , X (Decade) (10, 100, 1 ..); (Number of points) 100; , Y, (Linear); , (Nodes for analysis) 4.

 

5.3

 

Simulate. , () () RC - (. 5.4). , , . ( ) . fcp . f =0,1 f , f =10 f . .

 

5.4

 

3.2 RC

, 5.1 (. 5.5).

 

5.5. RC

 

f =0,1 f , f 10 f , RC , (. 5.6).

 

5.6 RC

 

0,1 f , f 10 f .

1. ?

2. ?

3. ?

4. RC RC ?

 






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