l3/t = 25 < 50:
= 0,012.
.
:
, 19;
;
;
, b=1;
, ;
( 0,3)
.
.
, .
2.2.
, , :
-
P1=P* ω/ 2* d1 = =300*0,308/(2*0,62) =74,51
ω - d1
;
d1- /2, h;
d1 = 1 = d + 2h = 0,4 + 2·0,11 = 0,62 ;
:
v = 9*l3 = 9*0,3= 2,7 /
q0:
;
;
= 7850/3;
, 10/c2.
12, M1, 1. 12 1
1, v, q0.
1
M1 = ΩΣγi q0i + γjp(1 + μ)1(y1 + y2) + γjv(1 + μ)Ω1
Ω - : γi, γjp, γjv -
(
v) : q0 -
: 1 + μ - ; y1 y2 -
P1; v -
, Ω1 - ,
v.
12, .
:
12 = 0,5·1,81+ 1,5·1,34·74,51·(0,52+0,072) + 1,2·1,34·2,7·0,68 = 92,86 ·:
1 = -0,92·1,81- 1,5·1,34·74,51·(0,18+0,212) - 1,2·1,34·2,7·0,92 = -64,6 ·,
1 + μ = 1 + 15/(37,5 + L) = 1 + 15/(37,5 + 6,0) = 1,34.
:
.
2.4. .
.
.
|
|
|
:
= 19,45·5,32/8 = 68,31 ͷ.
:
Q = 19,45·5,3/2 = 51,55 .
R1
():
300 = 1,8024Pγjp(1 + μ)/2 = 1,8024·300·1,5·1,31/2 = 532 .
200 = 1,8024Pγjp(1 + μ)/2 = 1,8024·200·1,5·1,31/2 = 354,67 .
: 
2.6. .
():
M= 532·(1,325 + 0,325)+ 354,67·0,825 = 1170,4 ·;
Q = 532·(1 + 0,62)+ 354,67·(0,43 + 0,06)= 1035,6 .
(-):
M- = γjv1(1 + μ)Ω1+ γjv2(1 + μ)Ω2 =1,2·1,31·9·3·2,36+1,2·1,31·2,5·3·1,156= 113,77 ·;
Q- = γjv1(1 + μ)Ω1+ γjv2(1 + μ)Ω2 =1,2·1,31·9·3·1,9+1,2·1,31·2,5·3·0,728= 89,35 .
: = + + - = 68,31 + 1170,4+113,77 = 1352,5 ·;
Q= Q + Q+ Q- = 51,55 + 1035,6+89,35 = 1176,6 .
:
.
2.7. .
