: 23.08.2013.
:
- .
- .
, . , , , . 1 . (. . .). . , . . ( ).
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| 1. |
:
φ + E 1 I 1 × r 1 = φ.
:
φ E 2 I 2 × r 2 = φ.
:
φ I 3 × r 3 + E 3 = φ.
:
φ I 4 × r 4 = φ.
, :
φ + E 1 I 1 × r 1 + φ E 2 I 2 × r 2 + φ I 3 × r 3 + E 3 + φ I 4 × r 4 = φ + φ + φ + φ
E 1 I 1 × r 1 E 2 I 2 × r 2 I 3 × r 3 + E 3 I 4 × r 4 = 0.
I × r , :
E 1 E 2 + E 3 = I 1 × r 1 + I 2 × r 2 + I 3 × r 3 + I 4 × r 4.
. , . . . . , . . ., .
1.
( 2).
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| 2. |
E = I × r 0 + I × r = I × (r 0 + r),
.
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| 3. 1 |
, .
1. ( 3). . . , :
E 1 + E 2 = I × r 1 + I × r 2; 1,9 + 1,3 = I × (2 + 3); 0,6 = 5 × I;
I = 0,12
, .
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2. ( 4). .
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4. 2
:
| 6 = 2 × I 1 + 5 × I 3. | (1) |
:
| 6 2 = 2 × I 1 4 × I 2; 2 = I 1 2 × I 2. | (2) |
:
| I 3 = I 1 + I 2. | (3) |
. , . I 3 (3) (1), :
6 = 2 × I 1 + 5 × I 1 + 5 × I 2;
:
(6 = 7 × I 1 + 5 × I 2) + (2 = I 1 2 × I 2)
(12 = 14 × I 1 + 10 × I 2) + (10 = 5 × I 1 10 × I 2).
, :
22 = 19 × I 1, I 1 = 1,156 ,
I 1 (1):
6 = 2 × 1,156 + 5 × I 3,
I 1 (2):
2 = 1,156 2 × I 2,
, I 2 .
