[1c84]
d1min =40 [1c84]
12
d1 =100
d2 = d1u(1-ε) =100∙3,58(1-0,02) = 351
ε = 0,02
d2 = 355
u = d2/d1(1 ε) = 355/100(1 0,02) = 3,62
Δu = (3,62 3,58)100/3,58 = 1,1% < 4%
a > 0,55(d1+d2) + H = 0,55(100+355) + 4,0 = 254
h = 4,0 K
= 300
L = 2a + w +y/4a
w = 0,5π(d1+d2) = 0,5π(100+355) = 715
y = (d2 - d1)2 = (355 100)2 =65025
L = 2∙300 + 715 +65025/4∙300 =1369
L =1400
a = 0,25{(L w) + [(L w)2 2y]0,5} =
= 0,25{(1400 715) +[(1400 715)2 - 2∙65025]0,5} = 317
α1 = 180 57(d2 d1)/a = 180 57(355-100)/317 = 134º
v = πd1n1/60000 = π100∙950/60000 = 5,0 /
Ft = N/v = 3,08∙103/5,0 = 616 H
Cp = 0,9
Cα = 0,89 α1 = 134º
l = 1,10 L/L0, L0=0,71
[] = 0CpCα
P0 = 2,2
[] = 2,2∙0,9∙0,891,10 = 1,94
Z = 10/[] = 103,08/1,94 =15,9
Z = 16
F0 = 850 /VCpCα =
= 850∙3,08/5,0∙0,89∙0,9 = 654 H
F = 2F0sin(α1/2) = 2∙654sin(134/2) =1203 H
σmax = σ1 + σ+ σv < [σ]p = 10 /2
σ1
σ1 = F0/A + Ft/2A = 654/121+616/∙2∙121 = 7,95 /2
= 0,5b(2H h)
b
b = (z 1)p + 2f = (16 1)2,4 + 23,5 = 43,0
= 0,543,0(24,0 2,35) =121 2
σ
σ = Eh/d1 = 80∙2,35/100 = 1,88 /2
E = 80 /2
σv = ρv210-6 = 1300∙5,02∙10-6 = 0,03 /2
ρ = 1300 /3
σmax = 7,95+1,88+0,03 = 9,86 /2
σmax < [σ]p
6
Ft = 3993
Fr =1481 H
Fa = 784 H
F = 1203 .
F = 12531/2 = 125511,71/2 = 2828
. 6.1
|
|
|
7 .
45,
: σ = 780 ;
[τ] = 10÷20
;
d1 > (16105,8103/π10)1/3 = 38
d1 = 40 ;
:
l1 = (1,2¸1,5)d1 = (1,2¸1,5)40 = 48¸60 ,
l1 = 50 .
:
d2 = d1+2t = 40+2×2,5 = 45,0 ,
t = 2,5 ;
d2 = 45 :
:
l2 1,5d2 =1,5×45 = 68 .
:
d4 = d2 = 45 .
:
d1 > (16511,7103/π15)1/3 = 55
d1 = 55 ;
:
d2 = d1+2t = 55+2×3,0 = 61,0 ,
t = 3,0 ;
d2 = 60 .
:
l2 1,25d2 =1,25×60 = 75 .
:
d4 = d2 = 60 .
:
d3 = d2 + 3,2r = 60+3,2×3,0 = 69,6 ,
d3 = 70 .
209 212 .
| d | D | B | 0 | ||
| 209 | 33,2 | 18,6 | |||
| 212 | 52,0 | 31,0 |
8
. 8.1
.
åmA = 67Ft1134BX = 0
XOZ
BX = 399367/134 =1997 H
åm = 67Ft1134X = 0
XOZ
= 399367/134 =1997 H
XOZ
MX1 =199767 =133,8 ͷ
.
åmA = 67Fr +134BY Fa1d1/2 89F = 0
YOZ
BY = (120389 + 78452,99/2 148167)/134 = 214 H
åm = 223F 134Y + 67Fr + Fa1d1/2 = 0
YOZ
Y = (2231203 +148167 + 78452,99/2)/134 = 2898 H
YOZ
MY =120389 = 107,1 ͷ
MY =1203156 289867 =-6,5 ͷ
MY = 21467 = 14,3 ͷ
:
= (2 + Y2)0,5 = (19972 +28982)0,5 =3519 H
B= (B2 + BY2)0,5 = (19972 + 2142)0,5 =2008 H
. 8.2
.
åm = 68Ft 268F +136DX = 0
D XOZ
DX = (2682828 683993)/136 = 3576 H
D
åmD = 68Ft + 132F 136CX = 0
D XOZ
|
|
|
X = (1322828 + 683993)/136 = 4741 H
XOZ
MX1 =474168 =322,4 ͷ
MX2 =2828132 =373,3 ͷ
.
åm = 68Fr + Fad2/2 136DY = 0
D XOZ
DY = (681481+784267,01/2)/136=1510 H
D
åmD = 68Fr Fad2/2 +136CY = 0
C XOZ
CY = (784267,01/2 68∙1481)/136 = 29 H
XOZ
MY1 = 2968 = 2,0 ͷ
MY2 =151068 =102,7
:
C = (47412 +292)0,5 = 4742 H
D = (35762 +15102)0,5 = 3882 H
9
P = (XVFr + YFa)K
;
V = 1 ;
Fr ;
Y ;
K =1,3 ;
= 1 .
Fa/Co = 784/18,6×103 = 0,042 = 0,24 [1c. 131]
.
Fa/ =784/3519= 0,22 < e, =1,0; Y= 0
= (1,013519+0)1,31 = 4575
= (573ωL/106)1/m,
m = 3,0
= 4575(57327,822000/106)1/3 = 32253 < C = 33,2
.
= 106(33,2×103 /4575)3/60×265 = 24035 , > [L]=22000
9.2
Fa/Co = 784/31,0×103 = 0,025 = 0,21 [1c. 131]
C.
Fa/C =784/4742= 0,16 < e, =1,0; Y= 0
= (1,014742+ 0)1,31 = 6165
= (573ωL/106)1/m,
m = 3,0
= 6165(5735,5522000106)1/3 = 25402 < C = 52,0
.
= 106(52,0×103 /6165)3/60×53=188705 , > [L]=22000
