k1
: + 12 12
k-1
= 10-6, 12 1 /.
10-6 = [C12]/[C][12]= [C12]/1×1
[C12] = 10-6 /.
2. 2+ = 2 + 2
= 1, [CO] = 3 /; [2] = 4 /.
.
[CO] [2] ,
= [CO2] [2]/ [CO] [2]
1 = ×/(3-)(4-) = 2/(3-)(4-)
2 = 12 3 4 + 2
= 1,7 /
[CO] = 4 = 4 1,7 = 3,3 /
[2] = 3 1,7 = 2,3 /
[CO2] = [2] = = 1,7 /.
¹1, 2 = 12 7 + 2
2(1-) 12 + 7 = 0, :
2+ + = 0
= 12; = 1-, = 7
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