.


:




:

































 

 

 

 


()




 

Ba2+, Sr2+, Ca2+, Pb2+.

: Ba2+ − [Xe]; Sr2+ − [Kr];

Ca2+ − [Ar].

( H2SO4)=2 /3 :

(BaSO4)=1,11010; (SrSO4)=3,2107;
(aSO4)=2,5105; (PbSO4)=1,6108.

( Pb(OH)2), . .

, aSO4. Ca2+ . Ca2+ . Ca2+ . Ca2+, .

BaSO4, SrSO4, aSO4 . 20 . , BaSO4, H2SO4.

. (NH4)2[a(SO4)2]. aSO4 . Ca2+ - 50-60% , aSO4. Ca2+.

Ba2+, Sr2+, Ca2+, Pb2+ :

(BaO3)=4,01010; (SrO3)=1,11010;
(aO3)=3,8109; (PbO3)=7,51015.

, , HCl, HNO3, CH3COOH.

aO3 :

aO3 + 2 + 2 → (3)2.

, .

 

 

4.3.1. Ba2+

Ba2+ .

Ba2+ :

1. - Ba2+ BaCrO4 :

Ba2+ + CrO42 → BaCrO4↓; (BaCrO4)=2,31010,

, (HCl, HNO3) , - -, BaCr2O7, SrCr2O7, CaCr2O7 .

2. 䳿 Ba2+ - :

Cr2O72 + 2 2CrO42 +2+;

CrO42 + Ba2+ → BaCrO4↓.

Sr2+ Ca2+ =3-5. BaCrO4 . Pb2+ , - , .

Sr2+ Ca2+ SrCrO4, CaCrO4 䳿 , Cr2O72 , . Ba2+ Sr2+ Ca2+.

3. (NH4)2C2O4 Ba2+ BaC2O4, HCl, HNO3 3:

 

 

4. Na2HPO4 Ba2+ , HCl, HNO3 3: :

Ba2+ + HPO42 BaHPO4↓;

:

3Ba2+ + 2HPO42 + 2 Ba3(PO4)2↓ + 22.

5. ϳ . - .

 

4.3.2. Sr2+

Sr2+ .

1. Sr2+, , . , :

CaSO4 + Sr2+ → SrSO4↓ + Ca2+.

, Sr2+, . Ba2+, , - .

2. 䳿 Sr2+ - :

C2O42 + Sr2+ → SrC2O4↓,

, , .

3. - . , , .

Sr2+ .

4.3.3. 2+

a2+ .

1. a2+ :

CaCl2 + (NH4)2C2O4 → CaC2O4↓ + 2NH4Cl;

Ca2+ + C2O42 → CaC2O4↓.

, , , 1-2 . , , 3.

Ba2+ Sr2+ - , 2+ .

:

(Ba2O4)=1,6107; (Sr2O4)=5,6108; (a2O4)=2,57109.

, , . , Ba2O4 , Sr2O4.

, H2SO4, , , .

2. a2+ .

, (( H2SO4)=2,0 /3). . , , .

. CaSO42H2O

(( H2SO4)=2,0 /3), , . BaSO4 SrSO4 SO4. - , .

3. K2CrO4 (CrO42) a2+ CCrO4:

a2+ + CrO42 → CCrO4.

, ( ) .

4. a2+ 䳿 () NH4+- :

a2+ + [Fe(CN)6]4 + 2NH4+ → a(NH4)2[Fe(CN)6]↓.

, a2+, 4[Fe(CN)6] NH4Cl, . - () .

. . , Ba2+ 䳿 4[Fe(CN)6] a(NH4)2[Fe(CN)6]. ( ) . .

5. a2+ . - .

 

 





:


: 2015-11-05; !; : 1695 |


:

:

- , 20 40 . - .
==> ...

1765 - | 1715 -


© 2015-2024 lektsii.org - -

: 0.015 .