1. .
2. .
3. , .
4. , .
5. .
6. .
: (IV) 71 0,5 ?
:
m (Na2SO3) = 71 1. 71
n (H2SO4) = 0,5 Na2SO3 + H2SO4 = Na2 SO4 + SO2 + 2
: V(SO2) n = 1 n = 1
= 106/
M = 106
2. : 71: = 106: 1
= 71 * 1 / 106 = 0,67
0, 67 H2SO4, 0,5 , ,
H2SO4:
3. 71
Na2SO3 + H2SO4 = Na2 SO4 + SO2 + 2
n = 1 n = 1
= 106/ Vm = 22,4 /
m = 106 V = 22,4
4. : 71: 106 = : 22,4
= 71 * 22, 4 / 106 = 15,08
4. : 15,08 SO2
: , 20 60- ( 1,14) , 29,03 .
:
V(H2SO4) = 20 1. H2SO4
W(H2SO4) = 60% = 0,6 m(- H2SO4) = ρ * V = 1,14 / * 20 = 22,8
ρ((H2SO4) = 1.14 / 2. H2SO4
m(BaCl2) = 29,03 m(H2SO4) = 22,8 * 0,6 = 13,68
: m(BaSO4) 3. :
H2SO4 + BaCl2 = BaSO4 + 2l
4. :
13,68
H2SO4 + BaCl2 = BaSO4 + 2l
n = 1 n = 1
M=98/ M=208/
m = 98 m = 208
: 13,68 : 98 = : 208 = 29,035
13,68 H2SO4 29,035 BaCl2, 29,03 , . .
5. 29,03
H2SO4 + BaCl2 = BaSO4 + 2l
n = 1 n = 1
M=208/ M=233/
m = 208 m = 233
: 29,03 : 208 = : 233 = 32,5
6. : m(BaSO4) = 32,5