: 
= 
sin 
2
f()= 
- 6 
+
(+1) 
dx
,
= 
= 4
= 
= 0; y = 1
1+ 
+ 
++ 
+
5
= l n s 3
= 
[3; 4]
l n dx
,
= 2 - = 0
= - 
= 3; y = 4
6
= tqx
= 1+4 sin x 2x [0;]
s dx
,
= s 
+ = 0
1+ 
+ 
++ 
+
7
= (1- l n )
= x 7,5 +18
dx
,
= , =1; =0
- =0
|
|
|
8
* 
(1+4) 
= 3 
= -3+4 sin x + 2x [; 2]
dx
,
= + = +1
- 
=
9
= (1+5)
