.
| Ft, H | ||
| Fr, H | ||
| Fa, H | ||
| T, H | ||
ω, c 
| 58.7 | 14.7 |
3- 4- , .
, , F, , , .
8.5.1 yz ( ).
∑=0 Rdy 2l1-Ft l1=0,
Rdy=(Ft l1)/ 2l1= Ft /2.
Rdy=4800/2=2400 H Rcy=Rdy=2400 H
. ∑Fy=0 Rcy+Rdy-Ft=0
2400+2400-4800=0
8.5.2 z ( ).
∑=0; -Rd 2l1-Frl1+d/2=0,
Rd=(- Fr l1+ F d/2)/ 2l1= (-1801*65+1233*256/2)/2*65=314
∑Dy=0; -R 2l1+Frl1+ F d/2=0,
R=(Fr l1+ F d/2)/ 2l1= (1801*65+1233 *256/2)/2*65=2115
: ∑Fx=0 R- RD- Fr
2115-314-1801=0
8.5.3 YZ( )
1-1:
0<z2<l1=65;
1= Rcyz1 z1=0 M1=0
z1=65 M1=2400*0.065=156
8.5.4 Z( .
1-1:
0<z1<l1=65;
1= Rcz1 z1=0 M1=0
z1=65 M1=2115*0.065=137.4
11-11:
0<z2<l1=65;
2= RDz2 z2=0 M2=0
z2=65 M=314*0.065=-20.41
, .
8.5.5 3- ,
=y2+ x2 +T22=629
Dk=46
-
-
-
n2=560.8 , n3=140
: Ft=4800: Fr=1801 : Fa=1233.
Rc= √(Rcx)2+(Rcy)2=√2400+2115=3200
Rd= √(Rdx)2+(Rdy)2=√2400+314=2420
.
Fa/Ca=1233/31000=0.039
R=(0.56*1.0*3200+1.85*1300)*1.2=5036
|
|
|
L=10000000/60*95 *(40300/5036)3=11400
L10h>Lh , , , .
.
.
υ=0,3-12,5 /c . υ=1,56 /
---68. :
V=(0,48-0,8) =(0,48-0,8)*3,5=(1,68-2,8).
V- .
.
υ=1,5/, ( 1033-79). υ<2/. .
, , .
, 10.1.
10.1 .
| d | D | h1 | h2 |
, , . .
20( 1412-85) 30 ( 977-88); - 45( 1050-88); 8 /2
11.1
11.1 - -
| , , | d, | D, | L, | L, |
- 500-40-I.1-45-II.2- 21424-75
, .
.
, , , . :
, 80-100 ;
; , .
, , , , , .
. ( ).
|
|
|
. . ; .
, .
.
, , , , .
, , , .
, .
, . .
, .
, , , , , , , .
, , , .
: , , ; , .
.
, , .
, .
. . . . .
. . . . 189-45.
. .
, :
, , 4100L43, , 9,5 , 1460 , 50.
|
|
|
, , 165 , U=4, .
:
;
;
.
; ---68.
1. ,.. : /.. , .. .-:- ,2002.-36.
2. , .. . : - / .. , .. .- .:..,2005.-309.,.
3. , .. / .. . : ..,1999.-454 .
