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10. , 20,0 0,1 NaOH 16,0 0,08 HCl.

. , :

NaOH + HCl = NaCl + H2O

, , :

n 0(NaOH) = 20,0 ∙ 103 ∙ 0,1 = 2,0 ∙ 103 ;

n 0(HCl) = 16,0 ∙ 103 ∙ 0,08 = 1,28 ∙ 103 .

n 0(NaOH) > n 0(HCl), NaOH , , NaOH NaCl :

n 1(NaOH) = n 0(NaOH) n 0(HCl) = 2,0 ∙ 103 1,28 ∙ 103 =

= 0,72 ∙ 103 .

n 1(NaCl) = n 0(HCl) = 1,28 ∙ 103 .

NaCl pH .

(V) 20,0 + 16,0 = 36,0 .

NaOH :

(NaOH) = 0,72 ∙ 103/ 36 ∙ 103 = 0,02 /.

, (3.8) :

pH = 14 + lg C (NaOH) = 14 + lg(0,02) = 12,3

11. , 20,0 0,1 NaOH 36,0 0,08 HCl.

. , :

NaOH + HCl = NaCl + H2O

, , :

n 0(NaOH) = 20,0 ∙ 103 ∙ 0,1 = 2,0 ∙ 103 ;

n 0(HCl) = 36,0 ∙ 103 ∙ 0,08 = 2,88 ∙ 103 .

n 0(NaOH) < n 0(HCl), HCl , , HCl NaCl :

n 1(HCl) = n 0(HCl) n 0(NaOH) = 2,88 ∙ 103 2,0 ∙ 103 =

= 0,88 ∙ 103

n 1(NaCl) = n 0(NaOH) = 2,0 ∙ 103

NaCl pH .

(V) 20,0 + 36,0 = 56,0 .

HCl :

(HCl) = 0,88 ∙ 103/ 56 ∙ 103 = 0,0157 /.

, (3.3) :

pH = lg C (HCl) = lg(0,0157) = 1,8.

12. , 20,0 0,12 NaCN 15,0 0,09 HCl.

. , :

NaCN + HCl = HCN + NaCl

, , :

n 0(NaCN) = 20,0 ∙ 103 ∙ 0,12 = 2,4 ∙ 103 ;

n 0(HCl) = 15,0 ∙ 103 ∙ 0,09 = 1,35 ∙ 103 .

n 0(NaCN) > n 0(HCl), NaCN , , NaCN HCN :

n 1(NaCN) = n 0(NaCN) n 0(HCl) = 2,4 ∙ 103 1,35 ∙ 103 =

= 1,05 ∙ 103 ;

n 1(HCN) = n 0(HCl) = 1,35 ∙ 103 .

(V) 20 + 15 = 35 .

:

(NaCN) = 1,05 ∙ 103/ 35 ∙ 103 = 0,03 /;

(HCN) = 1,35 ∙ 103/ 35 ∙ 103 = 0,039 /.

, (3.15) :

pH = lg[ (HCN) / (NaCN)] = 9,3 lg(0,039 / 0,03) = 9,18

13. , 11,25 0,12 / NaCN 15,0 0,09 / HCl.

. , , :

NaCN + HCl = HCN + NaCl

n (NaCN) = 11,25 ∙ 103 ∙ 0,12 = 1,35 ∙ 103 ;

n (HCl) = 15,0 ∙ 103 ∙ 0,09 = 1,35 ∙ 103 .

n (NaCN) = n (HCl), 1,35 ∙ 103 HCN.

(V) 11,25 + 15,0 = 26,25 .

HCN :

(HCN) = 1,35 ∙ 103/ 26,25 ∙ 103 = 0,051 /.

, (3.5) :

pH = lg[ (HCN)] = ∙ 9,3 ∙ lg(0,051) = 5,3

14. , 20,0 0,12 / NaCN 35,0 0,09 / HCl.

. , , :

NaCN + HCl = HCN + NaCl

n 0(NaCN) = 20,0 ∙ 103∙ 0,12 = 2,4 ∙ 103 ;

n 0(HCl) = 35,0 ∙ 103 ∙ 0,09 = 3,15 ∙ 103 .

n 0(HCl) > n 0(NaCN), HCl HCN :

n 1(HCl) = 3,15 ∙ 103 2,4 ∙ 103 = 0,75 ∙ 103 ;

n 1(HCN) = 20,0 ∙ 103 ∙ 0,12 = 2,4 ∙ 103 .

HCl HCN, .

(V) 20,0 + 35,0 = 55,0 .

HCl :

(HCl) = 0,75 ∙ 103/ 55,0 ∙ 103 = 0,014 /.

, (3.3) :

pH = lg[(HCl)] = lg(0,014) = 1,87.

15. , 10,0 0,1 / Na2HAsO4 16,0 0,1 / HCl.

. :

Na2HAsO4 + HCl = NaH2AsO4 + NaCl (3.16)

NaH2AsO4 + HCl = H3AsO4 + NaCl (3.17)

:

n (Na2HAsO4) = 10,0 ∙ 103 ∙ 0,1 = 1,0 ∙ 103 ;

n (HCl) = 16,0 ∙ 103 ∙ 0,1 = 1,6 ∙ 103 .

Na2HAsO4 , HCl (3.16), (3.16) 1,0 ∙ 103 NaH2AsO4
(1,6 1,0) ∙ 103 = 0,6 ∙ 103 HCl. (3.17) H3AsO4 NaH2AsO4 :

n (NaH2AsO4) = 1,0 ∙ 103 0,6 ∙ 103 = 0,4 ∙ 103 ;

n (H3AsO4) = 0,6 ∙ 103 .

(V) 10 + 16 = 26 , 26 ∙ 103 .

:

(NaH2AsO4) = 0,4 ∙ 103/ 26 ∙ 103 = 0,015 /;

(H3AsO4) = 0,6 ∙ 103/ 26 ∙ 103 = 0,023 /.

, (3.15) :

pH = lg( (H3AsO4) / (NaH2AsO4)) =

= 2,22 lg(0,023/0,015) = 2,03.






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