-4:
D4(h4- h4) = KD1(h4- h3)→
→D4=0,815373D∙1,01(516,15-384,22)/(2758-293,435)=0,04408D /
-2 -3, :
:
=d∙N0+1∙1+22+3∙3+4∙4+5∙5+66.
d=1000/(Δh0∙η∙η)=1000/((3460,35-2366,28)∙0,97∙0,98)=0,9615 /,
( )
Δh0=h0-hK.
η=0,97 η=0,98.
.
D1 = D1=0,0365993D /,
D2 = D2=0,0874498D /,
D3 =D3+ D+D= 0,10145D+75 /,
D4 = D4=0,04408D /,
D5 =D5 +D=0,004666D+33,384 /,
D6 =D6 +D+D+D=0,038616D+17,04535 /.
.
y1=(h1-h)/(h0-h)=(3204,5-2366,28)/(3460,35-2366,28)=0,766
y2=(h2-h)/(h0-h)=(3072-2366,28)/(3460,35-2366,28)=0,645
y3=(h3-h)/(h0-h)=(2931,5-2366,28)/(3460,35-2366,28)=0,516
y4=(h4-h)/(h0-h)=(2758-2366,28)/(3460,35-2366,28)=0,358
y5=(h5-h)/(h0-h)=(2552,5-2366,28)/(3460,35-2366,28)=0,1702
y6=(h6-h)/(h0-h)=(2492-2366,28)/(3460,35-2366,28)=0,115
7.3. . D=0,9615∙80+0,0365993D∙0,766+0,0874498D∙0,645+(0,10145D+75)∙0,516+
+0,04408D∙0,358+(0,004666D+33,384)∙0,1702+(0,038616D+17,04535)∙0,115
→D=146,36/ = 526,896 /.
.
D1 = D1=0,0365993D=5,35 /=19,26 /,
D2 = D2=0,0874498D=12,799 /=46,076 /,
D3 =D3+ D+D= 0,10145D+75=89,85 /=323,46 /,
D4 = D4=0,04408D=6,45 /=23,22 /,
D5 =D5 +D=0,004666D+33,384=34,07/=122,652 /,
D6 =D6 +D+D+D=0,038616D+17,04535=22,708 /=81,75 /.
D1+ D2+ D3+ D4+ D5+ D6 =171,227 / = 616,417 /.
.
:
D=D-(D1+ D2+ D3+ D4+ D5+ D6)=
=146,36-171,227= -24,867 /.
, .
:
D=D2-D6- D- D=-24,946 /.
.
.
NH=[Σ (Dn *(h0- hn )+DΔh0] η η
N1=D1(h0-h1)η η=5,35(3460,35-3204,5)0,97*0,98=1,301 .
N2=D2(h0-h2)η η=12,799(3460,35-3072)0,98*0,97=4,725 .
N3=D3(h0-h3)η η=89,85(3460,35-2931,5)0,98*0,97=45,170 .
|
|
N4=D4(h0-h4)η η=6,45(3460,35-2758)0,98*0,97=4,306.
N5=D5(h0-h5)η η=34,07(3460,35-2552,5)0,98*0,97=29,402 .
N6=D6(h0-h6)η η=22,708(3460,35-2492)0,98*0,97=20,903 .
N=D(h0-h)η η=25,862 .
d = D / N =146,36/80=1,8295 (/) = 6,5862 (/)
Q=D(h0-h)=146,36(3460,35-1089,26)=347,033 .
9.3. [4]
.
9.4. [2]:
η= (N*1000/ Q)100%=23,05 %.
η= (N*1000/ Q)100%=33,75%.
η=((N*1000+ Q)/ Q)100%= 54,75 %.
.
, , . 2 1 1,28*137,3*3,6=490,3 / 2 . 2 250 /.
-250-180-3,
.
( ) D = 35,73 /= 120 /.
2 -60-125,