1) :
= 2 + (-1),
2 , (-1) N α, α .
2) :
= (-1) + R + L,
(-1) k, k , R k ( ), L .
3) ω:
ω = = 2 + (-1) - (-1) - R - L
ω =2 + R L .
,
.
ω =2 + R L
ω≥0
2 + R L≥0
≤ 2 + R L.
.
.
1) =1, R=0, L=0;
2) =2 + (-1)=2 + (1-1) = 2;
3) { , , { N } }={ , } (!);
4) ω =2 + R L= 2+1--0-0 = 3 ;
5) ≤ 2 + R L= 2+1-0-0 = 3.
4.6.2. (=1)
ω = 3 = 3-1 = 2
ω =
.
α D ,
(.1).
4.6.3. (=2).
ω = 3 = 3-2 =1
ω<
()
= () L = L , 1 2.
1 2 L = L , ; D D (. 2).
4.6.4. (=3).
ω = 3 = 3-3 =0.
ω<
.
1, 2 3 - Ρ = = , -
; :
L = L , L = L , L = L (. 3).
4.6.5. .
D , D ,, L = L , L = L ,, Ρ = = , ( ), ( ).
|
|
.
.
1) =2, R=0, L=0;
2) = 2 + (-1) = 2 + (2-1) = 2 + ;
3) { , , { N } }={ , , { N } };
4) ω =2 + R L = 2+2--0-0 = 4 ;
5) ≤ 2 + R L = 2+2-0-0 = 4.
4.7.2. (=1).
= 2 + = 2+1 = 3,
{ , , { N } }= { , , { N }
ω = 4 = 4-1 = 3.
ω =
, , N
-N
N 1 D , (.1).
4.7.3. (=2).
= 2 + = 2+2 = 4,
{ , , { N } }= { , , N , N },
ω = 4 = 4-2 = 2.
ω<
, , N , N
()
N = N (, ) S 1,
N = N (, ) S 2.
N
N 1 2 S S , ; D D (.2).
4.7.4. (=3).
= 2 + = 2+3 = 5,
{ , , { N } }= { , , N , N , N }
ω = 4 = 4-3 = 1.
ω<
, , N , N , N
()
N = N () = () L 1,
N = N () = () L 2,
N = N () = () L 3.
N
N 1, 2, 3 L , L , L , ; S S , S S , S S (.3).
4.7.5. (=4).
= 2 + = 2+4= 6,
{ , , { N } }= { , , N , N , N , N },
ω = 4 = 4-3 = 1.
ω<
, , N , N , N , N
.
N
N 1, 2, 3, 4 P , P , P , P , (.4); , ( .4 ).
4.7.6. N .
N D , D ,, S , S ,, L , L ,, P , P , N ( ).