.


:




:

































 

 

 

 


( )




 

1) :

= 2 + (-1),

2 , (-1) N α, α .

2) :

= (-1) + R + L,

(-1) k, k , R k ( ), L .

3) ω:

ω = = 2 + (-1) - (-1) - R - L

ω =2 + R L .

 

,

.

 

ω =2 + R L

ω≥0

2 + R L≥0

≤ 2 + R L.

 

.

 

.

 

1) =1, R=0, L=0;

2) =2 + (-1)=2 + (1-1) = 2;

3) { , , { N } }={ , } (!);

4) ω =2 + R L= 2+1--0-0 = 3 ;

5) ≤ 2 + R L= 2+1-0-0 = 3.

 

4.6.2. (=1)

 

ω = 3 = 3-1 = 2

ω =

.

α D ,

(.1).

 

4.6.3. (=2).

 

ω = 3 = 3-2 =1

ω<

()

= () L = L , 1 2.

1 2 L = L , ; D D (. 2).

 

4.6.4. (=3).

 

ω = 3 = 3-3 =0.

ω<

.

1, 2 3 - Ρ = = , -

; :

L = L , L = L , L = L (. 3).

 

4.6.5. .

 

D , D ,, L = L , L = L ,, Ρ = = , ( ), ( ).

 

.

 

.

 

1) =2, R=0, L=0;

2) = 2 + (-1) = 2 + (2-1) = 2 + ;

3) { , , { N } }={ , , { N } };

4) ω =2 + R L = 2+2--0-0 = 4 ;

5) ≤ 2 + R L = 2+2-0-0 = 4.

 

4.7.2. (=1).

 

= 2 + = 2+1 = 3,

{ , , { N } }= { , , { N }

ω = 4 = 4-1 = 3.

ω =

, , N

-N

N 1 D , (.1).

 

4.7.3. (=2).

 

= 2 + = 2+2 = 4,

{ , , { N } }= { , , N , N },

ω = 4 = 4-2 = 2.

ω<

, , N , N

()

N = N (, ) S 1,

N = N (, ) S 2.

N

N 1 2 S S , ; D D (.2).

 

4.7.4. (=3).

 

= 2 + = 2+3 = 5,

{ , , { N } }= { , , N , N , N }

ω = 4 = 4-3 = 1.

ω<

, , N , N , N

()

N = N () = () L 1,

N = N () = () L 2,

N = N () = () L 3.

N

N 1, 2, 3 L , L , L , ; S S , S S , S S (.3).

 

4.7.5. (=4).

 

= 2 + = 2+4= 6,

{ , , { N } }= { , , N , N , N , N },

ω = 4 = 4-3 = 1.

ω<

, , N , N , N , N

.

N

N 1, 2, 3, 4 P , P , P , P , (.4); , ( .4 ).

 

4.7.6. N .

 

N D , D ,, S , S ,, L , L ,, P , P , N ( ).





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