ΔQ | / 3 | |||
− | % |
-20-13
1.1.1
h = 960 (.4 Ж2013)
1.1.2 . L = 17
1.1.3
h = (ξ W/2 ρ + h)
1.1.3.1
ρ = G/V 273/(u + 273) 98000/101300
1.1.3.2
G = ρol + dz/1500 + 1,306 α V0 = 0,950 + 10/1500 + 1,306 1,35 3,265 =6,713
ρ = 6,713/6,651 273/(200 + 273) 98000/101300 = 0,564 /3
1.1.3.3
ξ = 0,5 z2 = 0,5 9 = 4,5
1.1.3.4
h = ξ ω2/2 ρ n, n
h = 0,55 2,5482/2 0,564 10 = 10,07
h = 4,5 2,5482/2 0,564 + 10,07 = 17,373
1.1.4 : W = 16
1.1.4.1 :
, d < 0,9 λ = 0,04
h = λ L/d W2/2 ρ = 0,04 17/0,559 162/2 0,564 = 87,819
1.1.4.3 :
ρ = G/V 273/(u + 273)98000/101300 = 6,713/6,651273/(160 + 273)98000/101300 =
= 0,616 /3
1.1.4.4 :
h = ξ ω2/2 ρ
h = 1 162/2 0,616 = 78,848
1.1.4.5
h = h + h = 87,819 + 78,848 = 166,667
1.1.5
1.1.5.1
V. = Bp V m, m ( m = 1)
V. = 0,381 6,651 1 = 2,534
1.1.5.2 ( )
ω = 17 /
1.1.5.3
, d < 0,9 λ = 0,04
1.1.5.4
1.1.5.5
h = λ /d W2/2 ρ,
h = 0,04 30/0,436 16,9812/2 0,616 = 244,44
1.1.5.6
h = ξ ω2/2 ρ = 1,1 16,9812/2 0,616 = 97,694
1.1.5.7
h = h + h = 244,44 + 97,694 = 342,134
1.1.5.8
hc = g(1,23 1,293 273/(u + 273)) = 30 9,81 (1,23 1,293 273/(200 + 273)) =
= 142,36
1.1.5.9 Ж2013
H = h + h + h + h = 960 + 17,373 + 166,667 + 244,44 = 1380,48
1.1.5.11 ( )
= H hc = 1380,48 142,36 = 1246,12
1.2
2.1.1
|
|
V = BP (V + α V0) (υ + 273) / 273, α = 1,05
V = 0,381 (6,651 + 1,05 3,265) (200 + 273) / 273 = 6,654 /
2.1.2
V = β1 V 101300/98000 3600, β1 = 1,1
V = 1,1 6,654 101300/98000 3600 = 27235,180 3/
2.1.3
Hp = β1 = 1,1 1380,48 = 1527,328
T = V + 273 = 100 + 273 = 373
Hs = Hp T3 / T 98000/101300, T3 = 473 K (200˚C)
Hs = 1527,328 473 / 373 98000/101300 = 1873,705
2.1.4
15,5
..200˚
ⅅ.597 /
ą0,55
2.1.4.1 , :
N = (V Hs) / (3600 1000 η), η = 0,55
N = (27235,180 1873,705) / (3600 1000 0,55) = 25,77
2.1.4.2 :
= k N = 1,3 25,77 = 33,505
2.2.
..4A1804
...37
ⅅ..590 /
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