5.1.
(). , , , . :
RJ Rj ( ), ;
DLINA , ;
P Pi , , . .
5.2.
. . N N . ( ), . , , , . . , :
(n ):
N N
(m ):
N N S
(n+m) :
N N S
, :
N S k
, T, T, U, - , . .
. 1÷4.
. () .
5.3.
. , , , . . :
,
,
,
,
,
,
,
.
, . . 5 6.
1
1 .1
|
|
( )
2010.
110/10
592
10.5
N | N | i | Sj | j | j | cosφj | |
- | - | - | .. | .. | |||
35 | 0.46 | ||||||
35 | 0.02 | ||||||
35 | 0.25 | ||||||
0.1 | 0.75 | ||||||
35 | 0.16 | ||||||
35 | 0.48 | ||||||
0.3 | 0.8 | ||||||
35 | 2.00 | ||||||
35 | 0.08 | ||||||
0.5 | 0.85 | ||||||
16 | 2.1 | ||||||
35 | 0.6 | ||||||
0.7 | 0.9 | ||||||
35 | 1.0 | ||||||
0.9 | 0.95 |
2
2 .1
( )
2010 .
110/10
592
10.5
N | N | i | Sj | j | j | cosφj | |
- | - | - | .. | .. | |||
35 | 0.46 | ||||||
35 | 0.02 | ||||||
35 | 0.16 | ||||||
35 | 0.25 | ||||||
35 | 0.48 | ||||||
35 | 2.00 | ||||||
35 | 0.08 | ||||||
16 | 2.1 | ||||||
35 | 0.6 | ||||||
35 | 1.0 | ||||||
0.1 | 0.75 | ||||||
0.3 | 0.8 | ||||||
0.5 | 0.85 | ||||||
0.7 | 0.9 | ||||||
0.9 | 0.95 |
3
3 .1 ( )
2010 .
110/10
592
10.5
N | N | i | |
- | - | - | |
35 | 0.46 | ||
35 | 0.02 | ||
35 | 0.16 | ||
35 | 0.25 | ||
35 | 0.48 | ||
35 | 2.00 | ||
35 | 0.08 | ||
16 | 2.1 | ||
35 | 0.6 | ||
35 | 1.0 |
|
|
4
4 .1 ( )
2010 .
110/10
592
10.5
N | N | Sj | j | j | cosφj |
- | - | .. | .. | ||
0.1 | 0.75 | ||||
0.3 | 0.8 | ||||
0.5 | 0.85 | ||||
0.7 | 0.9 | ||||
0.9 | 0.95 |
5
5 10 .1
2010 .
110/10
592
10.5
------------------------------------------------------------------------------
HOMEP OTOK MOHOCT BETB:APKA: OTEP MOHOCT: OTEP: HAP.:
--------------------------------::-----------------:::
HAAA:KOHA:AKTBH:PEAKTBH.: T: AKTBH.: PEAKT.: HAP.: OB:
:::--------:----------:--------:--------:--------:--------:---------
:BETB:BETB: KBT: KBAP: OTH.E.: KBT: KBAP: KB: KB:
------------------------------------------------------------------------------
: 1: 2: 232.05: 155.84:.00:.28:.13:.011: 10.489:
: 2: 3: 7.50: 6.61:.00:.00:.00:.011: 10.489:
: 2: 4: 224.55: 149.22:.00:.01:.04:.014: 10.485:
: 3: 101: 7.50: 6.61:.10:.10:.05:.042:.418:
: 4: 5: 151.20: 113.40:.00:.02:.03:.019: 10.481:
: 4: 6: 73.35: 35.82:.00:.07:.01:.019: 10.481:
: 5: 104: 151.20: 113.40:.30:.74: 3.12:.130:.414:
: 6: 8: 46.57: 19.23:.00:.04:.02:.009: 10.472:
: 6: 7: 26.77: 16.59:.00:.00:.00:.019: 10.481:
: 8: 9: 21.38: 7.03:.00:.02:.00:.009: 10.463:
: 8: 10: 25.20: 12.20:.00:.00:.00:.001: 10.471:
: 7: 102: 26.77: 16.59:.50:.32:.71:.205:.411:
: 9: 105: 21.38: 7.03:.90:.56:.95:.004:.404:
: 10: 11: 25.20: 12.20:.00:.01:.00:.002: 10.468:
: 11: 103: 25.20: 12.20:.70:.49:.92:.301:.407:
------------------------------------------------------------------------------
6
6 10 .1
2010 .
110/10
592
10.5
10
===============================
- 694.64 .*
- 1.22 .* 0.18%
- 3.02 .* 0.44%
- 4.25 .* 0.61%
- 7.80 .* 1.12%
- 12.05 .* 1.73%
. * | ||||||||||
( ) | () | |||||||||
.* | % | .* | % | .* | % | .* | % | .* | % | |
694.6 | 7.80 | 1.12 | 3.02 | 0.44 | 1.22 | 0.18 | 4.25 | 0.61 | 12.05 | 1.73 |
5.4.
, . , . : (, ); () , ; ( , , , , ) . , .
|
|
:
-592. 105. 1,1. 0,95.
5.5.
, . . Pi, Qi . , , . , . 1 , ( ) P1-2, P2-3, P3-101, P2-4, P4-5, P5-104, P4-6, P6-7, P7-102, P6-8, P8-9, P9-105, P8-10, P10-11, P11-103, Pj P101, P102, P103, P104, P105, Pi :
1-2=101+102+103+104+105;
3-101=101;
5-104=104;
7-102=102;
9-105=105;
11-103=103;
2-3=3-101=101;
2-4=4-6+4-5=102+103+104+105;
4-5=5-104=104;
4-6=6-7+6-8=102+103 +105;
6-7=7-102=102;
6-8=8-9+8-10=103+105;
8-9=9-105=105;
8-10=10-11=11-103=103.
Qi.
-. ().
, ( ), , Pi Qi. (PTR) .
: PTR POTP. . . , , (.1) , 1-2 ( ), N N POTQ PTR . 3. POTP POTQ . 4. PTR Q i, Qi (. . 5).
7
POTP POTQ
PTR
N n/n | N | N | POTP | POTQ |
P101 | Q101 | |||
P104 | Q104 | |||
P102 | Q102 | |||
P105 | Q105 | |||
P103 | Q103 |
|
|
8
POTP POTQ
PTR
N n/n | N | N | POTP | POTQ |
7,50 | 6,61 | |||
151,20 | 113,40 | |||
26,77 | 16,59 | |||
21,38 | 7,03 | |||
25,20 | 12,20 |
VAO. (FORTRAN):
SUBROUTINE VAO(K,NIP)
COMMON /BL1/N1(200),N2(200),MAO(200)
MAO(1)=0
DO 1 I=1,K
IF(N1(I).EQ.NIP) GO TO 1
DO 3 J=1,K
IF(N1(I).NE.N2(J)) GO TO 3
MAO(I)=J
GO TO 1
3 CONTINUE
1 CONTINUE
RETURN
END
:
K ( );
N1 () ;
N2 ;
MAO ;
NIP () .
VAO (PASCAL):
procedure VAO(k,nip: integer);
var i,j: integer;
Begin
mao[1]:=0;
for i=1 to k do if n1[i]<>nip then
for j:=1 to k do if n1[i]=n2[j] then mao[i]:=j;
End;
: n1, n2 mao . , k nip, n1, n2 mao. VAO n1, n2 mao, ^ (, mao^[i]:=j;).
VAO (C/C++):
void VAO(int k, int nip, int *n1, int *n2, int *mao)
{
int i=0,j=0;
mao[0]=0;
for(i=0; i<k; i++) if(n1[i]!=nip)
for(j=0; j<k; j++) if(n1[i]==n2[j]) mao[i]=j;
}
PTR. (FORTRAN):
SUBROUTINE PTR(K,NIP)
COMMON /BL1/N1(200),N2(200),MAO(200)
COMMON /BL2/POTP(200),POTQ(200)
DO 1 I=1,K
IF(N1(I).EQ.NIP) GO TO 1
IF(POTP(I)) 3,1,3
3 P=POTP(I)
Q=POTQ(I)
N=I
4 M=MAO(N)
POTP(M)=POTP(M)+P
POTQ(M)=POTQ(M)+Q
IF(N1(M).TQ.NIP) GO TO 1
N=M
GO TO 4
1 CONTINUE
RETURN
END
PTR (PASCAL):
procedure PTR(k,nip: integer);
var i,n,m: integer;
p,q: real;
Begin
for i:=1 to k do if (n1[i]<>nip) and (potp[i]<>0) then
begin
p:=potp[i];
q:=potq[i];
n:=i;
m:=mao(i);
while n1[m]<>nip do
begin
potp[m]:=potp[m]+p;
potq[m]:=potq[m]+q;
n:=m;
m:=mao[n];
end;
end;
End;
PTR (/++):
void PTR(int k, int nip, int *n1, int *mao, float *potp,
float *potq)
{
int i=0,n=0,m=0;
float p=0.0,q=0.0;
for(i=0; i<k; i++) if((n1[i]!=nip)&&(potp[i]!=0)) {
p=potp[i];
q=potq[i];
n=i;
for(m=mao[i]; n1[m]!=nip;) {
potp[m]+=p;
potq[m]+=q;
n=m;
m=mao[n];
}
}
}
: POTP ; POTQ . PTR .
9
. 1
N n/n | N | N | POTP | POTQ |
232,05 | 155,84 | |||
7,50 | 6,61 | |||
224,55 | 149,22 | |||
7,50 | 6,61 | |||
151,20 | 113,40 | |||
73,35 | 35,82 | |||
151,20 | 113,40 | |||
26,77 | 16,59 | |||
46,57 | 19,23 | |||
26,77 | 16,59 | |||
21,38 | 7,03 | |||
25,20 | 12,20 | |||
21,38 | 7,03 | |||
25,2 | 12,20 | |||
25,2 | 12,20 |
|
|
10
POTP POTQ
PTR
( )
N n/n | N | N | POTP | POTQ |
7,50 | 6,61 | |||
151,20 | 113,40 | |||
26,77 | 16,59 | |||
25,20 | 12,20 | |||
21,38 | 7,03 |
PTR. - (PASCAL):
procedure PTR(k,nip: integer)
var i,j,n,m: integer;
p,q: real;
Begin
for i:=1 to k do if (n1[i]<>nip) and (potp[i]<>0) then
begin
for j:=1 to k do if i=mao[j] then
begin
break;
continue;
end;
p:=potp[i];
q:=potq[i];
n:=i;
m:=mao(i);
while n1[m]<>nip do
begin
potp[m]:=potp[m]+p;
potq[m]:=potq[m]+q;
n:=m;
m:=mao[n];
end;
end;
End;
, PTR PASCAL potp, potq, n1 mao . . , k nip, potp, potq, n1 mao. potp, potq, n1 mao, PTR ^ (, potp^(m):=potp^(m)+p;).
PTR (C/C++):
Void PTR(int k, int nip, int *n1, int *mao, float *potp,
float *potq)
{
int i=0,j=0,n=0,m=0;
float p=0.0,q=0.0;
for(i=0; i<k; i++) if((n1[i]!=nip)&&(potp[i]!=0)) {
for(j=0; j<k; j++) if(i==mao[j]) {
break;
continue;
}
p=potp[i];
q=potq[i];
n=i;
for(m=mao[i]; n1[m]!=nip;) {
potp[m]+=p;
potq[m]+=q;
n=m;
m=mao[n];
}
}
}
7
. 1
N n/n | N | N | POTP | POTQ |
232,05 | 155,84 | |||
7,50 | 6,61 | |||
151,2 | 113,4 | |||
7,50 | 6,61 | |||
224,55 | 149,22 | |||
73,35 | 35,82 | |||
151,20 | 113,40 | |||
46,57 | 19,23 | |||
26,77 | 16,59 | |||
26,77 | 16,59 | |||
21,38 | 7,03 | |||
25,20 | 12,20 | |||
25,20 | 12,20 | |||
25,2 | 12,20 | |||
21,38 | 7,03 |
5.6.
Uj (. . 1):
U2 = U1 DU1-2 = U DU1-2; U8 = U6 DU6-8;
U3 = U2 DU2-3 = U DU1-2 DU2-3; U102 = U7 DU7-102;
U4 = U2 DU2-4; U9 = U8 DU8-9;
U101 = U3 DU3-101; U10 = U8 DU8-10;
U5 = U4 DU4-5; U105 = U9 DU9-105;
U6 = U4 DU4-6; U11 = U10 DU10-11;
U104 = U5 DU5-104; U103 = U11 DU11-103.
U7 = U6 DU6-7;
(U101, U102, U103, U104, U105) , =10/0,4=25. Uj , , (. - .2.).
|
5.7.
. . , , r, x, r, x (Wp, Wq, P, Q, DP, DQ, DU, U . .) . . 3. . 4 (r, x, r, x), . 5.
. | ||
110/10 | ||
, | 10.0 | |
592 | ||
. , | ||
j . | 0.8 | |
, . | 694.64 | |
. , | 10.5 |
. | ||
110/10 | ||
, | 10.0 | |
592 | ||
. , | ||
j . | 0.8 | |
, . | 694.64 | |
. , | 10.5 |
. | ||
110/10 | ||
, | 10.0 | |
592 | ||
. , | ||
j . | 0.8 | |
, . | 694.64 | |
. , | 10.5 |
| |||
| |||||||