2.4.1. = f () .
. , = f () b 1 b 2: f () = b 1, f () = b 2, b 1 ¹ b 2.
2.2.1 , = b 1 + 1(), = b 2 + 2(). b 1 b 2 = 2() 1(). , , , . .
.
2.4.2. () z ()
, , ,
( () z ()) = () z (), (3)
( () × z ()) = () × z (). (4)
, , z () ¹ 0, ,
= . (5)
. () = b, z () = , 2.2.1 () = b + 1(), z () = + 2(). () z () = (b ) + (1() 2()), b , 1() 2() .
2.2.1 ,
( () z ()) = b = () z ().
()× z () = (b + 1())( + 2()) = bc + (b ×2() + c ×1() + 1()×2()),
bc , 3() = b ×2() + c ×1() + 1()×2() , 2.2.1
( () × z ()) = bc = () × z ().
, z () = ¹ 0,
= = .
v (x) = , 3() = c ×1() b ×2(),
= v (x)× 3(), (v (x)× 3()) = 0,
v (x) , 3() -
. ,
= = .
.
1. :
( × ()) = × ().
2. () = b m ,
( ()m) = ( ())m,
,
( m) = ( )m = a m.
2.4.3. u = u (x), y = y (x), v = v (x) , . u (x) £ y (x) £ v (x) u = u (x), v = v (x) , y = y (x) .
2.4.4. = f () , . = f () () , d- , ().
2.4.5. u (x) v (x) d- , , ¹ , u (x) < v (x) , u (x) £ v (x).
. u (x) = b, v (x) = c. , b £ c. , b > c.
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2.4.2 v (x) u (x) (v (x) u (x)) = c b, c b < 0, b > c.
2.4.4 d- , ( ¹ ) v (x) u (x) < 0, v (x) < u (x), . , b £ c, u (x) £ v (x). .
1) = 1; 2) = e.
1.
2. ?
3. ?
4. ? .
5. , ¥.
6. ? .
7. ?
8. . .
9. ? .
10. (),
11. ?
12. .
13. .
1
:
1. :
1) ; 2) ; 3) ;
4) ; 5) ; 6) .
7) ; 8) ; 9) ;
10) ; 11) ;12) ;
13) ; 14) ; 15) ; 16) ;
17) .
:
1) ; 2) ; 3) ;
4) ; 5) ; 6) ; 7) ;
8) .