. ..
-
-
.
519.682
. / . .. , .. .. , .. . - .: - , 2002. - 56 .
- .
:
. . .. ( 1,2),
..-.., .. ( 3,7),
..-., .. ( 8),
..., .. ( 3,4,5,6)
:
. .. ,
1. .. 3
2. .. 6
3. .. 15
4. .. 18
5. .. 23
6. .. 28
6.1 .. 28
6.2 .. 29
7. . 32
8. .. 39
9. .. 41
.. 55
1. 
. x n (n ).
#include <stdio.h>
#include <math.h>
main()
{int n;
float x;
char yn,temp;
do {
printf(" n-................");
scanf("%i",&n);
printf(" x-...........");
scanf("%g",&x);
if (fabs(x)<5)
printf(".........y(%g,%i)=%g\n",x,n,exp(log(log10(26-x*x))/n));
else if ((fabs(x)>5)&&(fabs(x)<sqrt(26))&&(n % 2))
printf(".........y(%g,%i)=%g\n",x,n,-exp(log(-log10(26-x*x))/n));
else if ((fabs(x)==5)&&(n>0))
printf(".........y(%g,%i)=%g\n",x,n,0/n);
else
printf(" \n");
printf(" -y, -n\n");
temp=getchar();
yn=getchar();
temp=getchar();
} while ((yn!='n')&&(yn!='N'));
}
:
| n | x | y |
| -4.8 | 0.912448 | |
| 5.05 | -0.787677 | |
| -4 | ||
y x. x a b ( a , b , ):
|
|
|
1. 
x=3,5; a=0.2; -1,5 b=2; 3
2. 
; x=0.3; a=2,1; 9,8 b=1; 6;
3. 
; x=1.03; a=2,5; 0,3; b=2; 3
4. 
; x=0.3; a=0,2; -1,2 b=6; -1
5. 
; x=1.3; a=0,2; 3,1; b=2; 3;
6. 
; x=2.3; a=1,2; -1,5; b=2; 3;
7. 
; x=1.03; a=1,2; 4,5; b=4; 1;
8. 
; x=1.03; a=-4; -5.2; b=6; 1
9. 
; x=2.3; a=-1.2; 0,3 b=2; 3
10. 
; x=-1.3; a=-2,2; 1,1 b=2; 3 11. 
; x=1.03; a=-1,2; 2,3 b=3; 2
12. 
x=3,5; a=0.2; -1,5 b=2; 3
13. 
; x=0.3; a=2,1; 9,8 b=1; 6;
14. 
; x=1.03; a=2,5; 0,3; b=2; 3
15. 
; x=0.3; a=0,2; -1,2 b=6; -1
16. 
; x=1.3; a=0,2; 3,1; b=2; 3;
17. 
; x=2.3; a=1,2; -1,5; b=2; 3;
18. 
; x=1.03; a=1,2; 4,5; b=2; 3;
19. 
; x=1.03; a=-4; -5.2; b=6; 1
20. 
; x=2.3; a=-1.2; 0,3 b=2; 3
21. 
; x=-1.3; a=-2,2; 1,1 b=2; 3
22. 
; x=1.03; a=-1,2; 2,3 b=3; 2
23. 
; x=1.3; a=0,2; 3,1; b=4; 5;
24. 
; x=2.3; a=1,2;-1,5; b=4; 5;
25. 
; x=1.03; a=1,2; 4,5; b=2; 3;
. x,y :
#include <stdio.h>
#include <math.h>
#define sq(t) ((t)*(t))
main()
{float x,y; char yn,temp;
do {
printf(" x...............");
scanf("%g",&x);
printf(" y...............");
scanf("%g",&y);
if (!(x==0)&&(((sq(x-1)+sq(y-1)<=1)&&((y>=x)&&(y>=1/x)||
(y<=x)&&(y<=1/x)))||((sq(x-1)+sq(y-1)>=1)&&((y>=x)&&
(y<=1/x)&&(x<0)||(y<=x)&&(y>=1/x)&&(x>0)))))
printf("........\n");
else
printf("... ....\n");
printf(" -y, -n\n");
temp=getchar(); yn=getchar(); temp=getchar();
} while ((yn!='n')&&(yn!='N')); }
:
| x | y | |
| 0.5 | ||
| 1.5 | ||
| -5 | -1 | |
| -2 | -0.01 | |
| -1 |
x,y :
1. 2.
3. 4.
5. 6.
7. 8.
9. 10.
11. 12.
13. 14.
15. 16.
17. 18.
19. 20.
21. 22.
23. 24.
25.
. S= 
. , , ,
, :
. , , .
#include <iostream.h>
main()
{ long double eps,s,y,x;
int n;
n=0;
eps=1.e-5;
s=0;
y=1.;
cin>>x;
while(fabs(y)>eps)
|
|
|
{ s=s+y;
n=n+2;
y=(-1)*y*x*x/(n*(n-1));
}
cout<<s<<" "<<n-2;
}
:
) x n ( ), S
;
) x n ( ), S ;
) x 
, S n. , :
1. 
2. 
3. 
4. 
5. 
6. 
7. 
8. 
9. 
10. 
11. 
12. 
13. 
14. 
15. 
16. 
17. 
18. 
19. 
20. 
21. 
22. 
23. 
24. 
25. 
1. .
: n=ak-110k-1+ ak-210k-2+...+a1101+a0. n 10 a0. n 10, n1: n1= ak-110k-2+ ak-210k-3+...+a2101+a1. n1 10 a1. , 0, n. . mk=mk-110+ ak-1, .
#include <iostream.h>
#include<math.h>
main()
{ int n,m,k;
m=0;
k=0;
cin>>n;
while(n>0)
{ m=10*m+n%10;
n=n/10;
k=k+1;
}
cout<<" :"<<k<<endl;
cout<<":"<<m<<endl;
2. n. n 0 5, .
10 . 10 . 10 .
#include <iostream.h>
#include<math.h>
main()
{ long int n,m,k,l;
m=0;
k=1;
cin>>n;
while(n>0)
{ l=n%10;
if(l!=5 && l!=9)
{ m=m+k*l;
k=k*10;
}
n=n/10;
}
cout<<m<<endl;
}
3. ,
. .
#include <iostream.h>
main()
{int n;
int i,j,k;
do
cin>>n;
while(n<=0 && n>27);
for(i=0;i<=9;i++)
for(j=0;j<=9;j++)
{ k=n-i-j;
if(k>=1 && k<=9)
cout<<i+j*10+k*100<<endl;
}
}
1. , N..
2. , .
3. N.
4. () L.
5. N : .
6. , N,
7. , N, .
8. , * , ( , , 38 83).
9. N.
10. , 13.
11. N. . N. . , LMN. , L, , N - , : L - N =+L++N
|
|
|
12. , : , .
13. 2. , . .
14. , . : [1] []; [] [I]. :[A][1]/[1][A]=3
15. , . .
16. . 7, . .
17. , 1 2, 2 3, 3 4, 4 5.
18. , 2 1, 3 - 2, 4 - 3, 5.
19. , 2 8, 3 - 4.
20. 7, 7. .
21. N. N 0 5, . , 1509 19..
22. N , , N- , (, 153 = I3 + 53 + 3). , .
23. 000000 999999. , : N1+N2+N3=N4+N5+N6.
24. , , .
25. - , , , , (), . , 34697 2 (3+4+6+9+7=29; 2+9=11; 1+1=2). N
26. L. , . , 6, 36 6, 25 - 625.
27. . , . , , .., . , , ( < 1.). , , , ,
28. , :
29. ;
30. ( ), .
31. k-
32. ) 12345678910111213, ;
|
|
|
33. ) 110100100010000100000, 10;
34. )149162536, , ;
)1123581321,
1. n.
1. n 1,2,3,..., n. , , [n/2+1,n-1] n .
#include <iostream.h>
main()
{ int n,d;
cin>>n;
for (d=1;d<=n/2;d++)
if(n%d==0)
cout<<d<<endl;
}
2. n, n. n .
#include <iostream.h>
main()
{ int n,d;
cin>>n;
for (d=1;d*d<n;d++)
if(n%d==0)
cout<<d<<", "<<n/d<<endl;
if(d*d==n)
cout<<d<<endl;
}
2. .
, :
n=q*m+r0,
m=q0*r0+r1,
r0=q1*r1+r2
..........................
rk-1=qk*rk+rk+1,
...........
rj-1=qj*rj,
rj .
#include <iostream.h>
main()
{ long int n,m,r,tmp;
cin>>n>>m;
if(m>n)
{ tmp=m; m=n; n=tmp;}
while(m>0)
{ r=n%m; n=m; m=r; }
cout<<n;
}
3. , n.
1.
, n.. , .
#include <iostream.h>
main()
{ int d,k,n;
cin>>n;
cout<<1<<endl<<2<<endl<<3<<endl;
k=5;
while (k<=n)
{ for (d=2;d*d<=k && k%d!=0;d++)
;
if(d*d>k)
cout<<k<<endl;
k=k+2;
}
}
1. N. .
2. N. ?
3. N.
4. 1 200, N.
5. 1 200, 5
6. 100 300, .
7. 1 10000 .
8. L, .
9. N.
10. 1 200, N.
11. N. .
12. ax3+bx2+cx+d=0, a,b,c,d .
13. p q q, p
14. n.
15. (1000, 9999) , , .
16. , ( < ). I, : < I < , .
17. N > 2. . L k , k- , , N Lk Lk+1;
18. N > 2. .
19. () , (,L,) = ((, L), M)
20. , N. , N
21. L (), : (K,L)=KL/ (K,L) M ( > 2) : N1,N2,..., N. (N1,N2,..., N), (N1,N2,..., N)= ((N1,N2,..., N-1), N) ..
|
|
|
22. , 0 1, 7 ( - )
23.. . -
24. , N. , ( , ). , 28 - , .. 28 = 1 + 2 + 4 + 7 + 14..
25. N. . , N . , ( )..
, . . .
1. .
#include <iostream.h>
main()
{ const int n=5;
int m[n]={-1,-2,-1,3,-5};
int I;
for (I=0;I<n && m[I]<=0;I++)
;
if(I>=n)
cout<<no;
else
cout<<m[I];
}
2. , n.
2.
. . , .
#include <iostream.h>
main()
{ long d,k,n,m,i;
long p[100];
cin>>n;
k=5; m=0;
p[0]=3;
cout<<1<<endl<<2<<endl<<3<<endl;
while (k<=n)
{ for (i=0;i<=m && p[i]*p[i]<=k && k%p[i]!=0;i++)
;
if(i>m || p[i]*p[i]>k)
{ cout<<k<<endl;
m=m+1;
p[m]=k;
}
k=k+2;
}
}
