.


:




:

































 

 

 

 


(Kt) (n)

(Kt) (n) Û x × Kt z + + y × n z .

.

= (g + [Kt z + ]) x × (g [n z ]) y, (46)

+, ; g + , g ; [Kt z + ], [n z ] , /3.

, , . (46)

= [ Kt z + ] x × [n z ] y. (47)

. .

: , .

() - , , . , < , .

[Kt z + ] [n z ] L (/3)

[Kt z + ] = x × L; [n z ] = y × L. (48)

[(Kt) (n) ] = (x × L) x × (y × L) y; (49)

L = . (50)

 

 

 

1. , 0,024 /3.

F2Û 2+ + 2F . (48)

[2+]= L; [ F ]= 2× L.

(47)

(F2) = [2+]∙[ F ]2 = L ×(2 L)2 =L 3 = 4 × (0,024)3 = 5,53 × 10-5.

2. 25 0,1 3 0,005 0,3 3 0,002 , (AgI) = 1,1×10-16?

 

AgNO3 + KI = AgI↓ + KNO3,

Ag+ + I = AgI↓.

[Ag+] = 0,005 /3; [I] = 0,002 /3.

[Ag+] = = = 1,25∙10-3 /3;

[I] = = = 1,5∙10-3 /3 .

(47) ()

(AgI) = [Ag+]×[I]= 1,25∙10-3 ∙1,5∙10-3 = 1,88×10-6.

AgI,

(AgI) > (AgI).

3. ( ) / /, , [3(4)2] = 6,3 10-39.

3(4)2↓↔ 32+ + 2 , (47)

[3(4)2] = [2+]3 [ ]2.

(48)

[2+] = 3× L; [ ] = 2× L.

(50) L = /.

2(3(4)2) = 602 /, , /

L = 602 9 10-9 = 5,42 10-6 /.

[2+] = 3× L = 3 9 10-9 = 2,7 10-8 /;

[ ] = 2× L = 9 10-9 2 = 1,8 10-8 /.

4. , 1 0,1 [Ag(NH3)2]NO3, 1 :

) 1×105 r; ) 1×105 I.

. [8]

([Ag(NH3)2]+) = 5,9 108; (AgBr) = 5,3 1013; (AgI) = 8,3 1017.

[Ag(NH3)2]NO3 [Ag(NH3)2]+ + NO .

[Ag(NH3)2]+

([Ag(NH3)2]+) = .

[NH3] ≈ 2 (NH3) = 1 /, , .

,

[[Ag(NH3)2]+] ≈ 2([Ag(NH3)2]NO3) = 0,1 /.

Ag+

[Ag+] = /.

Br , AgBr (AgBr)

[Br ] = /.

([Br ] = 8,98×105 /3) ([Br ] = 1×105 /3), .

I, AgI

[I] = /.

([I ] = 1,41×108 /3) ([I ] = 1×105 /3),

[Ag(NH3)2]NO3 + 2I = AgI↓ + NO3 + 2NH3.

 

 



<== | ==>
. |
:


: 2018-10-14; !; : 390 |


:

:

.
==> ...

1940 - | 1712 -


© 2015-2024 lektsii.org - -

: 0.016 .