4.7. , Q :
(Q) = 2Q 18; FC = 100.
) ;
) , .
:
) TC = Q² 18Q + 100;
FC = 100;
VC = Q² 18Q;
ATC = Q 18 + 100 / Q;
AFC = 100 / Q;
AVC = Q 18.
) Q = 10.
4.8. : (Q) = 2Q 18 FC = 100. .
: Q = 10 ( ). Q = 10 , Q = 10, .
4.9. , 4,5 20 . ., , 20%, .
: 2 ..
4.10. : TC= Q² 18Q + 100.
, , = 30. ?
: Q = 10, , 196 :
PR(Q=10) = TR TC = 30 × 10 (10² 18 × 10 + 100) = 280;
MC = P; => Qopt (2Q 18 = 30) = 24
, PR(Q=24) = TR TC = 30 × 24 (24² 18 × 24 + 100) = 476.
4.11. (Q) = 23,5 + Q.
: .
4.12. ,
TC = 20Q Q².
: .
5. .
. . . . . ( , ) . . . . . . . . . .
. . . . .
. . , ; . .
. . .
|
|
, , .
: .
.
(L), :
(P MC) / P = |1 / Ed|.
: .
. 4 .. :
Q, . | TC | FC | VC |
1. , .
2. , .
3. , :
) ,
) .
:
1. , , :
Q | TR | FC | VC | TC | AFC | AVC | ATC | AR | MC | MR | PR |
- | - | - | - | - | - | - | - 150 | ||||
- 150 | |||||||||||
2,66 | 12,66 | - 130 | |||||||||
2,0 | 7,0 | 1,33 | - 90 | ||||||||
1,6 | 4,6 | - 30 | |||||||||
1,33 | 3,33 | 0,8 | |||||||||
1,58 | 1,26 | 2,84 | |||||||||
1,36 | 1,27 | 2,64 | 1,33 | ||||||||
1,25 | 1,33 | 2,58 | |||||||||
1,20 | 1,44 | 2,64 | |||||||||
1,20 | 1,6 | 2,8 | - | - |
2. , (.5.1).
. 5.1. .
3. ) .
, ( FC = 150 .. ).
( 4 ..)
((P MC) / P = |1 / Ed|) , .
:
|
|
P = 4 = MR = AR.
: , . () . D = MR = AR. .
) .
, , :
MC = MR = .
: Q = 5 Q = 125 . Q = 5 150 .., Q = 125 . (PR = 170 ..). , Q = 125 . MC = P = 4 = MR = AR.
:
MC = P = MR = AR.
, Q= 5 . Q = 75 . , . , (FC = 150 ..) , : (FC + VC PQ) < FC( AVC < P, VC < PQ). :
, min AVC ≤ P < min ATC. .
AVC ≥ P, , .. .
75 .. AC < P.
:
: minAVC ≤ P < minATC.
, , P ≥ min AC. , :
MR = AR = MC = AC = P.
, . . : P = AC = MC.
(. 5.2).
5.2. .
:
. ((P MC) / P = |1 / Ed|) .
(D = AR).
, (/2).
, (/2).
MCMR. TR TC.
. :
TC = ¼ Q² + 10Q + 300;
Q(1) = 400 2P(1);
Q(2) = 600 4P(2).
) , , , ?
) .
) , , ?
:
, , , . .
|
|
. : , , . .
, , .
:
) :
MC = MR(1) =MR(2),
1, 2 , .
, . , , .
:
(TC) = MC = ½Q + 10.
, :
MC = ½ (Q(1) + Q(2)) + 10.
(MR(1) MR(2)) . : MR =(TR) = (P × Q).
Q(1) = 400 2P(1), Q(2) = 600 4P(2), , :
P(1) = 200 ½ Q(1)
P(2) = 150 ¼ Q(2).
:
MR(1) =(TR) =((200 ½ Q) × Q) = (200Q ½ Q²) = 200 Q(1);
MR(2) =(TR) =((150 ¼ Q) × Q) = (150Q ¼ Q²) = 150 ½Q(2).
:
(2) (1). :
Q(2) = 2 Q(1) 100.
Q(2) Q(1):
½ (Q(1) + 2Q(1) 100) + 10 = 200 Q(1).
, , :
Q(1) = 96 ;
Q(2) = 92 .
, :
P(1) = 200 ½ × 96 = 152 ..
P(2) = 150 ¼ × 92 = 127 ..
) : PR = TR TC.
TR = (Q(1) × P(1) + Q(2) × P(2)) =(96 × 152 + 92 × 127) = 26 276 ..
TC = ¼ (Q(1) + Q(2))² + 10(Q(1) + Q(2)) + 300 = (¼ × 188² + 10 × 188 + 300) = 11 016 ..
PR = 15 260 ..
) , , ?
. , , , . (.. ).
, . :
|
|
Q(D) = (400 2P(1)) + (600 4P(2))= 1 000 6P.
:
P = 167 1/6Q.
, . Q, MC = MR.
MC = ½Q + 10;
MR = (TR) = ((167 - 1/6 Q) × Q) = (167 Q 1/6 Q²) = 167 1/3 Q.
MC MR:
0,5Q + 10 = 167 1/3Q.
, Q ≈ 188 ., ≈ 167 1/6 × 188 ≈ 136 ..
: PR = TR TC.
PR = 188 × 136 (¼ × 188² + 10 × 188 + 300) = 14 552 ..
: 708 .. (15260 14552).