L, , , . Fmax = 4,3 , = =25 , / kb = b/e = 43 .
<e2(t)> , <e2 (t)> =D2/12. :
PB/Pe = <B2(t)>/< e2(t)> = 12 <B2(t)>/ D2.
, B(t) 1 < B(t) < 1
D = (Bmax Bmin)/(L1) = 2/(L1).
PB = <B2(t)> = 1/ 2, .
PB/Pe = <B2(t)>/< e2(t)> = 12 / (2 D2) = 3(L1)2/ 2,
:
(2.1)
- , :
= 100,1× ().
ʳ
2,58.104.
n
n ³ log2 L 1,443×ln L = 1,443×ln 2,58.104 = 14,66.
n= =15. L = 2n = 215 = 32768.
, = 1/(2f), f - . : = 1/(2f) = 1/(2×4,3) = 0,116 .
t = /n = 0,116/15 = 0,00775 = 7,75 .
, 1: (1) = 0, = 0,1 = 1.
() ( ) :
(2.1)
L ; iii . L = 1/L. (2.1) :
() = log2(1/L) = log2(1/32768) = 15 /.
1 0 max() = log2 2 = 1 /. , , (1) = = 0,1 , , (2) = 1 = 0,9, (2.1) :
p log2p (1 p) log2(1 p) =
= 0,1 log2 0,1 0,9 log2 0,9 = 0,1×1,443×ln 0,1 0,9×1,443×ln 0,9 =
= 0,1×1,443×(2,3) 0,9×1,443×(0,11) = 0,33+0,14 = 0,47.
: log2 z = ln z/ln 2 1,443 ln z.
. ϳ , . f ﳺ ()
|
|
R = f (). (2.2)
L = =1/L, (2.1) (2.2) ,
R = f log2 L = 2×4,3×103×15 = 1,29×105 /.
R = () / t = 0,47×/ 7,75×10-6 = 6,1×104 /.
ﳿ 1 ( ). .